Question

我可能会遗漏一些明显的东西，但是在libgdx中使用标签，它会显示一个字符串以显示我在指向随机字符串时遇到问题。

String Movie1 ="The Shawshank Redemption (1994)";
String Movie2="The Godfather (1972)";
String Movie3="The Godfather: Part II (1974)";
String Movie4="The Dark Knight (2008)";
String Movie5="Pulp Fiction (1994)";

randomNumber = random.nextInt(5) + 1;

MovieName= new Label(String,style)

我将把字符串指向什么以指向randomNumber与相应的电影。我无法投入电影＆＃34; + randomNumber，因为它只会说＆＃34; Movie5＆＃34;不是字符串

Answer 1

您是否尝试执行以下操作：String s = Movie + randomNumber以获取变量名称Movie1，Movie2等？除非变量是特定类的所有属性，否则这是不可能的。无论如何，你不应该试图这样做。相反，您应该使用数组或List<String>来保存变量。你可以这样做：

String[] movies = {"The Shawshank Redemption (1994)",
    "The Godfather (1972)",
    "The Godfather: Part II (1974)",
    "The Dark Knight (2008)",
    "Pulp Fiction (1994)"}

int randomNumber = random.nextInt(movies.length);

String myMovie = movies[randomNumber];

Answer 2

首先，你应该将你的字符串放入一个字符串数组或一个集合，例如ArrayList<String>，然后才可以通过随机索引号选择一个随机字符串。

如，

Random random = new Random();
String[] movies = {"The Shawshank Redemption (1994)",
   "The Godfather (1972)",
   "The Godfather: Part II (1974)",
   "The Dark Knight (2008)",
   "Pulp Fiction (1994)"};


// later somewhere else in a method or constructor...
int randomNumber = random.nextInt(movies.length);
String randomMovieTitle = movies[randomNumber];

Answer 3

您可以使用switch语句，例如：

var result;
randomNumber = random.nextInt(5) + 1;

switch(randomNumber) {
    case 1:
        result = Movie1;
        break;
    case 2:
        result = Movie2;
        break;
    case 3:
        result = Movie3;
        break;
}

Java指向随机变量

3 个答案: