Question

我的文件只包含

格式的行

new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003

是否可以使用bash将此输出解析为类似

的形式

7,59,0.876,0.000433344,0.00003

然后读到python？

Answer 1

sed 's/[^0-9,;.]//g;y/;/,/' YourFile

删除所有非数字，和。;
改变;到，

Answer 2

如果内容采用您提到的格式，您可以尝试使用以下sed命令

$ sed 's/^[^(]*(\([^)]*\))\s*;\s*\S*\s*=\s*\(\S\+\)\s*;\s*\S*\s*=\s*\(\S\+\)\s*;\s*\S*\s*=\s*\(\S\+\)$/\1,\2,\3,\4/' file
7,59,0.876,0.000433344,0.00003

Answer 3

使用sed：

sed 's/[^0-9,.][^0-9,.]*/ /g' input

更好的格式化：

 sed 's/[^0-9,.][^0-9,.]*/ /g' input | column -to,

给出：

7,59,0.876,0.000433344,0.00003

Answer 4

您可以grep获取数字：

$ grep -o '[0-9.]*' file
7
59
0.876
0.000433344
0.00003

使用-o标记，我们指示grep只是为了打印匹配的结果。这样，您拥有所有值，但不包含周围文本。

如果您希望以逗号分隔，请通过管道tr以逗号替换每个新行，最后到sed以使用新行替换最后一个逗号：

$ grep -o '[0-9.]*' a | tr -s '\n' ',' | sed 's/,$/\n/'
7,59,0.876,0.000433344,0.00003

Answer 5

使用gnu awk：

cat file

new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003
new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003

awk -F ' *[=()] *' -v RS=' ; |\n' -v OFS= -v ORS= 'NF{print $2, (NR%4==0)? "\n":","}' file
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003
7,59,0.876,0.000433344,0.00003

Answer 6

还使用FPAT gnu awk：

awk -v FPAT="[0-9.]+" '{for(i=1;i<=NF;i++)printf "%s%s", $i,(i!=NF?",":"\n")}'

试验：

$ echo "new file (7,59) ; lim = 0.876 ; dim = 0.000433344 ; r_d = 0.00003"|awk -v FPAT="[0-9.]+" '{for(i=1;i<=NF;i++)printf "%s%s", $i,(i!=NF?",":"\n")}'      
7,59,0.876,0.000433344,0.00003

FPAT可以做得更好。

Answer 7

许多解决方案，只有perl misisng;）

perl -nlE '$,=",";say m/[\d.]+/g'

将“列表分隔符”设置为,
仅匹配数字（返回列表）
打印列表

或（ofc）@ neronlevelu的解决方案

perl -plE 's/[^\d,;.]//g;y/;/,/'

删除任何不属于digit,;.
将;更改为'，'（y 会在搜索列表中找到所有出现的字符，其中包含替换列表中的相应字符） - aka { {1}}。

Answer 8

$ sed -r 's/[^0-9.]+/,/g;s/^,//' file
7,59,0.876,0.000433344,0.00003

$ awk -F'[^0-9.]+' -v OFS=',' '{$1=$1;sub(/^,/,"")} 1' file
7,59,0.876,0.000433344,0.00003

$ sed -r 's/[^0-9.,;]+//g;s/;/,/g' file
7,59,0.876,0.000433344,0.00003

$ awk -F';' -v OFS=',' '{$1=$1;gsub(/[^0-9.,]/,"")} 1' file
7,59,0.876,0.000433344,0.00003

我个人更喜欢最后两个，因为他们没有添加逗号然后再删除它，这总是让人觉得有点笨拙且容易出错。

将行输出解析为bash中的表

8 个答案: