我的文件看起来像
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所以在第一行之后，每一行都以括号中的数字开头。我需要用括号中的数字grep并将其输出到一个新文件中（不带[] ..这样就可以完成＆gt;
答案 0 :(得分：4)
grep -Po '(?<=\[)\d+(?=\])' file > new_file
-P用于Perl正则表达式，因此可以使用：
\d获取数字(?<=\[)和(?=\])） -o 仅匹配
答案 1 :(得分：2)
如果您的grep不支持-P选项但awk可用，则另一种可能是：
awk -F '[][]' '{ if ($2 != "") print $2 }' file > new_file
-F告诉awk接受]和[作为字段分隔符，$2然后包含您想要并打印的数字。
答案 2 :(得分：1)
使用简单命令分三步：
grep -v "//" inputfile | cut -d"[" -f2 | cut -d"]" -f1
在sed中你可以删除[]：
之外的所有内容grep -v "//" inputfile | sed 's/.*\[\(.*\)].*/\1/'