Question

XCode 6 B6

尝试创建一个可以从评估CGVector的逻辑创建的枚举，如下所示：

enum Direction:Int, Printable{
   case None = 0
   case North, South, East, West, NorthEast, NorthWest, SouthEast, SouthWest

   var description: String{
      switch (self){
      case .None:
        return "static"
      case .North:
        return "north"
      case .South:
        return "south"
      case .East:
        return "east"
      case .West:
        return "west"
      case .NorthEast:
        return "north-east"
      case .NorthWest:
        return "north-west"
      case .SouthEast:
        return "south-east"
      case .SouthWest:
        return "south-west"
      }
   }
}

extension Direction {
   func fromCGVector(vector:CGVector) -> Direction{
    var vectorDir = (dx:vector.dx, dy:vector.dy)
    switch(vectorDir){
    case (0.0, 0.0):
        return Direction.None
    case let (0.0,y) where y > 0.0:
        return Direction.North
    case let (0.0,y) where y < 0.0:
        return Direction.South
    case let (x, 0.0) where x > 0.0:
        return Direction.East
    case let (x, 0.0) where x < 0.0:
        return Direction.West
    case let (x, y) where x > 0.0 && y > 0.0:
        return Direction.NorthEast
    case let (x, y) where x > 0.0 && y < 0.0:
        return Direction.SouthEast
    case let (x, y) where x < 0.0 && y > 0.0:
        return Direction.NorthWest
    case let (x, y) where x < 0.0 && y < 0.0:
        return Direction.SouthWest
    default:
        return Direction.None
    }

 }
}

var test = Direction.fromCGVector(CGVector(dx:1.0, dy:1.0))

但是收到以下错误：＆＃39; CGVector无法转换为方向＆＃39;。

这对我没有意义，因为我没有尝试进行转换，只是调用Direction枚举的静态方法。我认为这可能是一个错误，但我想确保我没有遗漏任何明显的错误。

Answer 1

我相信您的意思是将该方法声明为static。看作枚举不能有任何公共构造函数，在类型而不是其中一个案例上调用实例方法是没有意义的。

extension Direction {
   static func fromCGVector(vector:CGVector) -> Direction?{
///...

var test = Direction.fromCGVector(CGVector(dx:1.0, dy:1.0))

来自CGVector的Swift枚举引发错误

1 个答案: