Question

我在数据库USER_DETAILS和Address中有两个表。这两个表的实体类都在

之下

@Entity
@Table(name="USER_DETAILS")
public class UserDetails {`

@Id @GeneratedValue(strategy=GenerationType.AUTO)
private int UserID;
private String UserName;

@OneToMany(cascade=CascadeType.ALL,fetch=FetchType.EAGER)
private List<Address> address=new ArrayList<>();

-------------------------------------------------------------
@Entity
public class Address {

@Id @Column(name="ADD_ID") @GeneratedValue(strategy=GenerationType.AUTO)
private int Id;
private String street;
private String city;

我想执行一个查询，以便它返回UserName =“user1”和的所有结果 address.city = 'City1' 当我执行sql查询

时

SELECT u.UserName,a.street
from USER_DETAILS u, Address a
where u.UserName='user1'
and a.city='City1';

结果是

+----------+---------+
| UserName | street  |
+----------+---------+
| user1    | street1 |
+----------+---------+

但是当我为上面的标准查询运行时

 Criteria criteria=session.createCriteria(UserDetails.class,"user")
                        .createAlias("address", "ad")
                        .add(Restrictions.eq("user.UserName", "user1"))
                        .add(Restrictions.eq("ad.street", "street2"));

它显示的结果与预期完全不同，

user1
City2 :: street2
City6 :: street6
City4 :: street4
City8 :: street8
City0 :: street0

我尝试了其他选项，例如createQuery("Address")而不是createAlias()。但结果相同。请提出你的建议。

谢谢

编辑：我使用的HQl查询类似于我用作sql的

List<Object[]> list=session.createQuery("select u.UserName,a.street "
        +" from UserDetails u,Address a"
        + " where u.UserName=:username and a.city=:cityname")
        .setString("username", "user1")
        .setString("cityname", "City1")
        .list();

我得到了与sql相同的结果，这是正确的结果。但标准没有显示正确的结果。

Answer 1

如下所示

<强> HQL / SQL

SELECT u.UserName,a.street
from USER_DETAILS u 
inner join u.Address ua
where u.UserName='user1'
and ua.city='City1';

标准API

Criteria c = session.createCriteria(UserDetails.class, "u");
c.createAlias("user.Address", "ua");
c.add(Restrictions.eq("u.UserName", "user1")
c.add(Restrictions.eq("ua.city", "City1");

请点击此处了解更多info。

Hibernate Criteria Api不提供准确的结果列表

1 个答案: