Question

以下是test webpage，其中包含method="post"

的表单

我需要输入值并将结果页面打印到the console。这是我的完整代码

import java.io.*;
import java.net.*;
import java.util.*;

class Post {
    public static void main(String[] args) throws Exception {
        URL url = new URL("http://chyngyz.com/test.php");
        Map<String,Object> params = new LinkedHashMap<String,Object>();
        params.put("fname", "Peter");
        params.put("lname", "Pen");

        StringBuilder postData = new StringBuilder();
        for (Map.Entry<String,Object> param : params.entrySet()) {
            if (postData.length() != 0) postData.append('&');
            postData.append(URLEncoder.encode(param.getKey(), "UTF-8"));
            postData.append('=');
            postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
        }
        byte[] postDataBytes = postData.toString().getBytes("UTF-8");

        HttpURLConnection conn = (HttpURLConnection)url.openConnection();
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
        conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length));
        conn.setDoOutput(true);
        conn.getOutputStream().write(postDataBytes);

        Reader in = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8"));
        for (int c; (c = in.read()) >= 0; System.out.print((char)c));
    }
}

执行但打印原始页面。看起来似乎没有提交参数。我该如何改进我的代码？

这是我的test.php

<form method="post" action="testResult.php">
First Name: <input type="text" name="fname"><br>
Last Name: <input type="text" name="lname"><br><br>
<input type="submit" value="Submit">
</form>

这是我的testResult.php

<?php
$fname= $_POST['fname']; 
$lname= $_POST['fname'];
?>
<p> Your name is 
<?php
print $fname . ' ' . $lname;
?> </p>

Answer 1

更改此行：

URL url = new URL("http://chyngyz.com/test.php");

由：

URL url = new URL("http://chyngyz.com/testResult.php");

如何使用Java提交帖子请求？

1 个答案: