Question

我有一个类似

的mysql表

id   title            date           filename
-----------------------------------------------
1    Sample Title    2014-10-08      file.pdf

2    Sample Title1   2014-07-09      file1.pdf

3    Title 3         2014-07-04      file2.pdf

在此列表中，我必须按日期顺序按顺序排序，以便我能够在第一个位置获取最后一条记录。为此，我用了

select * from table_name ORDER BY STR_TO_DATE( CONCAT( date ) , '%Y-%m-%d' ) DESC

我的pblm是我必须每月安排他们作为标题的月份

2014年7月-----＆gt; {标题} 在此标题下，应列出2014年7月表格中的记录等。请帮助解决问题。谢谢

Answer 1

你走了：

<?php
define("01","January");
define("02","Feb");
define("03","March");
define("04","April");
define("05","May");
define("06","June");
define("07","July");
define("08","Aug");
define("09","Sept");
define("10","Oct");
define("11","Nov");
define("12","Dec");

$con = mysql_connect("hostname","username","password");
if (!$con)
{
        die('Could not connect: ' . mysql_error());
}
mysql_select_db('trial', $con) or die( mysql_error());
$sql="select * from experiment group by date desc";
$result=mysql_query($sql);

echo "<table border=1>";
echo "<tr><th>title</th>"."<th>date</th>"."<th>filename</th></tr>";

$last_value=null;
while($row = mysql_fetch_array($result))
{     
        $date=$row['date'];
        $date_exploded = explode("-",$date);
        $value = $date_exploded[1];
        if($value == $last_value){
          echo "<tr><td>".$row['title']."</td><td>" .constant($value).</td><td>".$row['filename']."</td></tr>";
        }
        else{
          $last_value=$value;
          echo "<tr><td><div>separator</div></td><td>separator</div></td><td><div>separator</div></td></tr>";
          echo "<tr><td>".$row['title']."</td><td>" .constant($last_value)."</td><td>".$row['filename']."</td></tr>";
        }
}
        echo "</table>";
?>

根据您的样式格式随意更改分隔符div。我使用的数据库名为'trial'，我使用的表名为'experiment'

实验表架构是：

+----------+-------------+------+-----+---------+----------------+
| Field    | Type        | Null | Key | Default | Extra          |
+----------+-------------+------+-----+---------+----------------+
| id       | int(11)     | NO   | PRI | NULL    | auto_increment |
| title    | varchar(25) | YES  |     | NULL    |                |
| date     | date        | YES  |     | NULL    |                |
| filename | varchar(25) | YES  |     | NULL    |                |
+----------+-------------+------+-----+---------+----------------+

Answer 2

$query = <<<__EOQUERY__
  select concat(date_format(`date`, '%b'), ' ', year(`date`)) as `month`, `title`
    from `books`
   order by `date` desc
__EOQUERY__;

$connection = new MySQLi('localhost','root','calistoga','test');

$result = $connection->query($query);

echo "<table>";
$lastmonth = null;
foreach ($result as $row)
{   
    $month = $row['month'];
    $title = $row['title'];

    if ($month !== $lastmonth)
    {   
        echo "<tr><th>{$month}</th>";
        $lastmonth = $month;
    }   
    else
        echo "<tr><td></td>";

    echo "<td>{$title}</td></tr>";
}   
echo "</table>";

在MySQL中使用date_format（）格式化日期： http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_date-format
按实际日期值排序，而不是字符串值（这假定您的＆＃34;日期＆＃34;列是日期类型或其他时间值）

此处使用的表定义：

create table `books` (
  `id` integer not null auto_increment,
  `title` varchar(255) not null,
  `date`  date not null,
  `filename` varchar(255),
  primary key (`id`)
) engine=InnoDB;

insert into `books` (`title`,`date`,`filename`)
values
('sample title1', '2014-12-31', 'file1.pdf'),
('sample title2', '2014-11-30', 'file2.pdf'),
('sample title3', '2014-11-24', 'file3.pdf'),
('sample title4', '2014-10-20', 'file4.pdf');

mysql每月明智地列出php中表的记录？

2 个答案: