Question

我想问一些支持如何实现从PHP中的5个不同MYSQL脚本创建表的想法。它们各自的结果是按月计算的数据组的SUM。我不希望脚本花费大量时间，因为单独激活时它们都可以。

我会提出理论查询，以免我的信息很长。

<?php
$qry = "SUM(CASH) group by MONTH DESC";
$result=mysql_query($qry) or die(mysql_error());

$qry2 = "SUM(DEBT) group by MONTH DESC";
$result=mysql_query($qry2) or die(mysql_error());

$qry3 = "SUM(DEBTPAID) group by MONTH DESC";
$result=mysql_query($qry3) or die(mysql_error());

$qry4 = "SUM(INVOICE) group by MONTH DESC";
$result=mysql_query($qry4) or die(mysql_error());

$qry5 = "SUM(NVOICEPAYOFF) group by MONTH DESC";
$result=mysql_query($qry5) or die(mysql_error());
?>

我想要实现这样的表：

<table>
<tr>
  <td>CASH</td>
  <td>DEBT</td>
  <td>DEBTPAID</td>
  <td>INVOICE</td>
  <td>INVOICEPAYOFF</td>
</tr>
<?
echo '<tr>';

echo '<td><label>'. $row['CASH'] .'</label></td>';
echo '<td><label>'. $row2['DEBT'] .'</label></td>';
echo '<td><label>'. $row3['DEBTPAID'] .'</label></td>';
echo '<td><label>'. $row4['INVOICE'] .'</label></td>';
echo '<td><label>'. $row5['INVOICEPAYOFF'] .'</label></td>';
echo '</tr>';

?>
</table>

我将感谢您的每一个想法，解决方案或建议。先感谢您！

Answer 1

为什么不这样做？

SELECT sum(cash) as 'cash', sum(debt) as 'debt',
  sum(debtpaid) as 'debtpaid', sum(invoice) as 'invoice',
  sum(invoicepaid) as 'invoicepaid'
FROM my_table
GROUP BY MONTH DESC

从不同的脚本创建月度记录表

1 个答案: