Question

我有以下问题：

我有一张看起来像这样的表：

ArticleID|Group|Price
1|a|10
2|b|2
3|a|3
4|b|5
5|c|5
6|f|7
7|c|8
8|x|3

现在我试图得到这样的结果：

PriceA|PriceRest
13|30

意思是我想要汇总一列中a组的所有价格和另一列中其他所有的价格。

像这样的东西不起作用。

select 
    sum(Price) as PriceGroupA
    sum(Price) as PriceRest
from
    Table
where
    Group='a'
    Group<>'a'

有没有办法实现这个功能？

Answer 1

SELECT
sum(case when [Group] = 'a' then Price else 0 end) as PriceA,
sum(case when [Group] <> 'a' then Price else 0 end) as PriceRest
from
Table

Answer 2

请尝试：

select
    sum(case when [Group]='A' then Price end) PriceA,
    sum(case when [Group]<>'A' then Price end) PriceRest
from
    Table

SQL Fiddle Demo

Answer 3

您只需要两个子查询：

SELECT (SELECT SUM(PRICE)
        FROM Table1 
        WHERE [Group] ='a') AS PriceGroupA,
       (SELECT SUM(PRICE)
        FROM Table1 
        WHERE [Group]<>'a') AS PriceRest

Demo-Fiddle

特定于多个选择的位置

3 个答案: