我通过concurrent.futures的ThreadPoolExecutor下载了一个网址列表,但是在所有第一次尝试结束后,我可能会有一些超时网址要重新下载。我不知道该怎么做,这是我的尝试,但是无休止的打印失败' time_out_again':
import concurrent.futures
def player_url(url):
# here. if timeout, return 1. otherwise do I/O and return 0.
...
urls = [...]
time_out_futures = [] #list to accumulate timeout urls
with concurrent.futures.ThreadPoolExecutor(max_workers=10) as executor:
future_to_url = (executor.submit(player_url, url) for url in urls)
for future in concurrent.futures.as_completed(future_to_url):
if future.result() == 1:
time_out_futures.append(future)
# here is what I try to deal with all the timeout urls
while time_out_futures:
future = time_out_futures.pop()
if future.result() == 1:
print('time_out_again')
time_out_futures.insert(0,future) # add back to the list
那么,有什么方法可以解决这个问题吗?
答案 0 :(得分:1)
Future
个对象只能使用一次。 Future
本身对返回结果的函数一无所知 - ThreadPoolExecutor
对象负责创建Future
,返回它,并在后台运行函数:
def submit(self, fn, *args, **kwargs):
with self._shutdown_lock:
if self._shutdown:
raise RuntimeError('cannot schedule new futures after shutdown')
f = _base.Future()
w = _WorkItem(f, fn, args, kwargs)
self._work_queue.put(w)
self._adjust_thread_count()
return f
class _WorkItem(object):
def __init__(self, future, fn, args, kwargs):
self.future = future
self.fn = fn
self.args = args
self.kwargs = kwargs
def run(self):
if not self.future.set_running_or_notify_cancel():
return
try:
result = self.fn(*self.args, **self.kwargs) # sefl.fn is play_url in your case
except BaseException as e:
self.future.set_exception(e)
else:
self.future.set_result(result) # The result is set on the Future
如您所见,当函数完成时,结果将在Future
对象上设置。因为Future
对象实际上并不知道提供结果的函数,所以无法尝试使用Future
对象重新运行该函数。您所能做的就是在超时发生时返回url
和1
,然后重新submit
到ThreadPoolExecutor
的网址:
def player_url(url):
# here. if timeout, return 1. otherwise do I/O and return 0.
...
if timeout:
return (1, url)
else:
return (0, url)
urls = [...]
with concurrent.futures.ThreadPoolExecutor(max_workers=10) as executor:
while urls:
future_to_url = executor.map(player_url, urls)
urls = [] # Clear urls list, we'll re-add any timed out operations.
for future in future_to_url:
if future.result()[0] == 1:
urls.append(future.result()[1]) # stick url into list