谁在读他的! 谢谢您抽出宝贵的时间来研究这个问题。
我目前正在尝试开发一种快速的网页抓取功能,以便可以抓取大量文件。
这是我当前拥有的代码:
import time
import requests
from bs4 import BeautifulSoup
from concurrent.futures import ProcessPoolExecutor, as_completed
def parse(url):
r = requests.get(url)
soup = BeautifulSoup(r.content, 'lxml')
return soup.find_all('a')
with ProcessPoolExecutor(max_workers=4) as executor:
start = time.time()
futures = [ executor.submit(parse, url) for url in URLs ]
results = []
for result in as_completed(futures):
results.append(result)
end = time.time()
print("Time Taken: {:.6f}s".format(end-start))
这可以带来网站(例如www.google.com)的搜索结果, 但是我的问题是我不知道查看它带来的数据 我只会得到未来的物品。
请有人可以解释/告诉我如何做。
感谢您随时提供帮助。
答案 0 :(得分:1)
您也可以通过dict理解来实现它,如下所示。
with ProcessPoolExecutor(max_workers=4) as executor:
start = time.time()
futures = { executor.submit(parse, url): url for url in URLs }
for result in as_completed(futures):
link = futures.get(result)
try:
data = result.result()
except Exception as e:
print(e)
else:
print("Link: {}, data: {}".format(link, data))
end = time.time()
print("Time Taken: {:.6f}s".format(end-start))