UIApplication openUrl不使用格式化的NSString

Question

我有以下代码来打开谷歌地图：

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

但它不起作用且没有错误。它只是没有打开。

Answer 1

URLWithString需要一个转义百分比的字符串。您的示例网址包含空格，导致创建无NSURL。此外，addressString还可能包含需要转义的字符。首先尝试以百分比形式转义url字符串：

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
NSString *escaped = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:escaped]];  

Answer 2

需要转义urlString， else [NSURL URLWithString：urlString]将返回nill。

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding] ]];