在java中,我读取一个图像,然后浏览像素,如果它的颜色距离是< 30,然后我想通过将其alpha更改为0来清除图像。这是我的代码:
但这不起作用。它没有效果......
有没有人看到这个问题?
由于
import java.awt.Color;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import javax.imageio.ImageIO;
public class Recognize {
public static void main(String args[]) throws IOException {
Path path = Paths.get("images/fish.png");
File file = path.toFile();
if (file.exists()) {
InputStream stream = Files.newInputStream(path);
BufferedImage bufferedImage = ImageIO.read(stream);
int width = bufferedImage.getWidth();
int height = bufferedImage.getHeight();
if (width > 0 && height > 0) {
int TLpixel = bufferedImage.getRGB(0, 0);
Color TLcolor = new Color(TLpixel);
for (int i = 0; i < width; i++) {
for (int j = 0; j < height; j++) {
int pixel = bufferedImage.getRGB(i, j);
Color color = new Color(pixel);
double distance = ColourDistance(TLcolor, color);
//System.out.println(distance);
if (distance < 30) {
int mc = (0 << 24) | 0x00ffffff;
int newcolor = pixel & mc;
bufferedImage.setRGB(i, j, newcolor);
}
}
}
File outputfile = new File("images/fish_new.png");
ImageIO.write(bufferedImage, "png", outputfile);
}
}
}
public static int[] printPixelARGB(int pixel) {
int alpha = (pixel >> 24) & 0xff;
int red = (pixel >> 16) & 0xff;
int green = (pixel >> 8) & 0xff;
int blue = (pixel) & 0xff;
return new int[] {red, green, blue, alpha};
}
public static double ColourDistance(Color c1, Color c2) {
double rmean = ( c1.getRed() + c2.getRed() )/2;
int r = c1.getRed() - c2.getRed();
int g = c1.getGreen() - c2.getGreen();
int b = c1.getBlue() - c2.getBlue();
double weightR = 2 + rmean/256;
double weightG = 4.0;
double weightB = 2 + (255-rmean)/256;
return Math.sqrt(weightR*r*r + weightG*g*g + weightB*b*b);
}
}
答案 0 :(得分:2)
通过&#34;清除&#34;你明显意味着像素使像素透明&#34;。
为了能够使像素透明,图像必须支持透明像素。 BufferedImage
是否支持透明像素取决于BufferedImage
的类型。使用BufferedImage
加载ImageIO
后,您几乎不知道图像的类型。但是你可以通过将图像传递给这样的方法,轻松地将图像转换为具有已知类型(支持透明度)的图像:
public static BufferedImage convertToARGB(BufferedImage image)
{
BufferedImage newImage = new BufferedImage(
image.getWidth(), image.getHeight(),
BufferedImage.TYPE_INT_ARGB);
Graphics2D g = newImage.createGraphics();
g.drawImage(image, 0, 0, null);
g.dispose();
return newImage;
}