Question

这段代码似乎应该可行。它总结了＆＃34;条纹＆＃34; （letter-consonant-letter-etc.）然后返回总和。但是，当我使用print (striped("My name is ...") )对其进行测试时，它只计算my和is并给我一个2而不是3 ...为什么name会丢失？

VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"


def striped(text):

    my_sum = 0
    text = text.replace(".", " ").replace(",", " ").split()
    vowels = VOWELS.lower()
    consonants = CONSONANTS.lower()

    for word in text:
        word = word.lower()
        if ((word[::2] in vowels and word[1::2] in consonants)\
        or (word[::2] in consonants and word[1::2] in vowels))\
        and len(word) > 1:
            print (word)
            my_sum += 1

    return my_sum

Answer 1

您应该使用set.issubset()代替。

VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"

def striped(text):

    my_sum = 0
    text = text.replace(".", " ").replace(",", " ").split()
    vowels = set(c for c in VOWELS.lower())
    consonants = set(c for c in CONSONANTS.lower())

    for word in text:
        word = word.lower()
        if ((set(word[::2]).issubset(vowels) and set(word[1::2]).issubset(consonants))\
        or (set(word[::2]).issubset(consonants) and set(word[1::2]).issubset(vowels)))\
        and len(word) > 1:
            print (word)
            my_sum += 1
    return my_sum        

striped('My name is...')

它适用于my和is的原因是它们是两个字符，因此您要检查m是否在常量字符串中，以及{{1}在元音串中，它起作用。对于y之类的较长字词，显然name不在sonsonants字符串中，因此失败。

相反，你应该使用集合。基本上，您想要查找nm是否是辅音集的子集。

Answer 2

这是一个包含列表的解决方案。您的代码存在的问题是，当您使用[::2]而不是单个字符时，超过两个字符的字会返回子字符串，而不会测试它们是否包含在vowels / constants中。通过首先将其转换为列表，您可以检查列表中的每个项目是否包含在相应的字符集中。

VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"


def striped(text):

    my_sum = 0
    text = text.replace(".", " ").replace(",", " ").split()
    vowels = VOWELS.lower()
    consonants = CONSONANTS.lower()

    for word in text:
        word = word.lower()

        if ((all(c in vowels for c in list(word[::2]))\
            and all(c in consonants for c in list(word[1::2])))\
        or (all(c in consonants for c in list(word[::2]))\
            and all(c in vowels for c in list(word[1::2]))))\
        and len(word) > 1:
            print (word)
            my_sum += 1

    return my_sum

print striped("My name is")

列出python中的切片问题

2 个答案: