百分比列表切片

时间:2012-11-16 20:14:03

标签: python

我正在使用python 3.2.3 IDLE,这是我的代码:

originalList = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]

newList = orginalList[0.05:0.95] #<<<<I have no idea what I'm doing here
print (newList)

我有一个原始的数字列表,它们是1 - 100,我想从原始列表中创建一个新列表,但是新列表必须只有属于5%的子范围的数据 - 95%的原始清单

所以新列表必须像[5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18....95]。我怎么做?我知道我的newList代码是错误的

7 个答案:

答案 0 :(得分:17)

originalList.sort()
newList = originalList[int(len(originalList) * .05) : int(len(originalList) * .95)]

答案 1 :(得分:5)

sl = slice(4, 95)
print(originalList[sl])

另见http://docs.python.org/2/library/functions.html#slice

答案 2 :(得分:4)

size = len(originalList)
newList = originalList[0.05*size - 1:0.95*size + 1]

答案 3 :(得分:1)

我还会使用列表理解来创建原始列表......不容易出错。

originalList = range(1,101)
newList = originalList[(len(originalList)*.05)-1:len(originalList)*.95]
print newList

给出了理想的结果......

编辑:在下面的评论中更改范围更简洁。

答案 4 :(得分:0)

如果您想获得列表的一部分,则语法为

List = [1,2,3,4,5,6,7,8,9,10]
newList = [*start index*:*Index to end AT*]

所以,第一个数字是子列表开始的索引,而第二个数字是子列表停止的索引(包含的索引) )。

希望这有帮助!

答案 5 :(得分:0)

对于任意长度的列表,您可以这样做:

>>> l = range(200)
>>> percentage = 5
>>> skip = int(len(l) * (float(percentage) / 100) / 2)
>>> len(l[skip:-skip])
190

答案 6 :(得分:0)

您可以使用fidx模块,该模块允许将百分比用作索引:

import fidx

originalList = fidx([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100])
# or better: originalList = fidx.list(range(1,101))

newList = originalList[0.05:0.95]

print (newList)

返回

[6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95]