Question

我正在为文本冒险游戏创建一个对话树，该游戏使用列表来保存对话选项。当用户从列表中选择一个选项时，它会响应，然后从列表中删除该选项，以便用户无法再次选择它。问题是，一旦我选择了一个选项（循环的第一个实例），第二个选择总是会返回错误。

以下是代码：

x = 1
dec1 = '"Why are you doing this? What do you want?"'
dec2 = '"You keep talking about Thread. What is it?"'
dec3 = '"Can you help me?"'
dec4 = 'Say nothing.'
decision = [dec1, dec2, dec3, dec4]

while x == 1:

    for i in decision:
        print '%d. %s' % (decision.index(i) + 1, i)

    current_input = input.return_input(charstate)

    if isinstance(current_input, int):
        if int(current_input) > len(decision) or int(current_input) < 1:
            print '\n"I don\'t understand, %s."' % charstate.charname
            continue
        elif int(current_input) == decision.index(dec1) + 1:
            print 'text'
            decision.remove(dec1)
        elif int(current_input) == decision.index(dec2) + 1:
            print 'text'
            decision.remove(dec2)
        elif int(current_input) == decision.index(dec3) + 1:
            print 'text'
            decision.remove(dec3)
        elif int(current_input) == 4:
            print 'text'
            x += 1
        else:
            exit(1)
    else:
        print '\n"I don\'t understand, %s."' % charstate.charname
        continue

问题似乎是在我选择一个选项后，if条件会返回错误，因为decision.index（dec＃）不再存在。至少，这是我能够弄清楚的。具体错误是“ValueError：x不在列表中”。我正在试图找到一种方法来设置它，以便不会发生这种情况。

我唯一的想法就是为每个选项创建单独的try ... except语句，这看起来非常不优雅和臃肿。我必须要有一些简单的东西。

谢谢大家！

edit：input.return_input（charstate）是一个只返回raw_input的函数。 “charstate”是一个保存当前角色信息和选择历史的对象 - 它在事件和场景之间传递。

Answer 1

通过索引从数组中删除，我相信这将为您提供所需的功能

dec1 = '"Why are you doing this? What do you want?"'
dec2 = '"You keep talking about Thread. What is it?"'
dec3 = '"Can you help me?"'
dec4 = 'Say nothing.'
decision = [[dec1,'text1'], [dec2,'text2'], [dec3,'text3'], [dec4,'text4']]

while True:

    for i in decision:
        print '%d. %s' % (decision.index(i) + 1, i[0])

    current_input = input.return_input(charstate)

    if isinstance(current_input, int):
        if int(current_input) > len(decision) or int(current_input) < 1:
            print '\n"I don\'t understand, %s."' % charstate.charname
            continue
        elif int(current_input) in xrange(1,len(decision)):
            print '%s' % (decision[int(current_input)-1][1])
            del decision[int(current_input)-1]
        elif int(current_input) == 4:
            print 'text'
            break
        else:
            exit(1)
    else:
        print '\n"I don\'t understand, %s."' % charstate.charname
        continue

Answer 2

好的，我实际上已经想出了如何做我需要做的事情。假名的答案对我来说是一个很好的第一步，但后来我意识到我需要根据答案实际运行单独的代码，而不仅仅是打印不同的代码。

我重新构建了代码，因此我不需要调用索引来确定选择了哪个答案。这实际上是一个相对简单的修复，一旦我了解它。

    dec1 = '"Why are you doing this? What do you want?"'
    dec2 = '"You keep talking about Thread. What is it?"'
    dec3 = '"Can you help me?"'
    dec4 = 'Say nothing.'
    decision = [dec1, dec2, dec3, dec4]

    while True:

        for i in decision:
            print '%d. %s' % (decision.index(i) + 1, i)

        current_input = input.return_input(charstate)

        if isinstance(current_input, int):

            current_input = int(current_input)

            if current_input - 1 in xrange(0, len(decision)):
                response = decision[current_input - 1]
            elif current_input - 1 not in xrange(0, len(decision)):
                print '\n"I don\'t understand, %s."\n' % charstate.charname
                continue
            else:
                exit(1)
        else:
            print '\n"I don\'t understand, %s."\n' % charstate.charname
            continue

        if response == dec1:
            print 'dec1'
        elif response == dec2:
            print 'dec2'
        elif response == dec3:
            print 'dec3'
        elif response == dec4:
            print 'dec4'
            break
        else:
            exit(1)

        del decision[current_input - 1]

if为对话树修改列表时的语句异常

2 个答案: