Question

我的SQL请求需要一些帮助。我有这张桌子：

CREATE TABLE `contact` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `first_name` varchar(65) DEFAULT NULL,
  `last_name` varchar(65) DEFAULT NULL,
  `phonenumber` varchar(45) NOT NULL,
  `avinumber` varchar(45) DEFAULT NULL,
  `date` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
  `source` varchar(45) NOT NULL,
  `nbrtryies` int(11) NOT NULL DEFAULT '0',
  `treaty_at` date DEFAULT NULL,
  `comment` varchar(255) DEFAULT '',
  `status` varchar(45) DEFAULT 'KO',
  `campagne_id` int(11) NOT NULL,
  `treated_by` int(11) DEFAULT NULL,
  `nodetree_id` int(11) DEFAULT NULL,
  `avi` varchar(45) DEFAULT NULL,
  `sessionid` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `id_UNIQUE` (`id`),
  KEY `fk_contact_campagne1_idx` (`campagne_id`),
  KEY `fk_contact_agent1_idx` (`treated_by`),
  CONSTRAINT `fk_contact_agent` FOREIGN KEY (`treated_by`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
  CONSTRAINT `fk_contact_campagne1` FOREIGN KEY (`campagne_id`) REFERENCES `campagne` (`id`) ON DELETE CASCADE ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=82 DEFAULT CHARSET=latin1;

我需要计算列数时的行数和行数：

treated_by

具有特定值，并按该列

对结果进行分组

Thsi就是我所做的，但我似乎没有工作：

SELECT 
    co.treated_by AS userId,
    COUNT(*) AS treated,
    SUM(CASE WHEN ca.userId=1 THEN 1 ELSE 0 END) AS total
FROM
    contact AS co
        INNER JOIN
    campagne AS ca ON ca.id = co.campagne_id
WHERE
    (co.date BETWEEN '2013-07-09' AND '2014-08-15')
        AND co.treated_by IN (2 , 40)
GROUP BY co.treated_by

这就是我得到的：

----------------------------
| userId | treated | total |
----------------------------
|    2   |    5    |   5   |
----------------------------
|   40   |    3    |   3   |
----------------------------

我需要这样的东西：

----------------------------
| userId | treated | total |
----------------------------
|    2   |    5    |   20  |
----------------------------
|   40   |    3    |   20  |
----------------------------

非常感谢你的帮助

Answer 1

GROUP BY co.treated_by，它产生记录COUNT（*）AS处理5和3，所以SUM（CASE WHEN ca.userId = 1 THEN 1 ELSE 0 END）AS总计，不可能超过20和20。

Answer 2

如果条件是co.treated_by，那么为什么逻辑包含ca.userId？

也许这会奏效：

SELECT co.treated_by AS userId,
       COUNT(*) AS treated,
       SUM(co.treated_by) AS total
FROM contact co INNER JOIN
     campagne ca
     ON ca.id = co.campagne_id
WHERE (co.date BETWEEN '2013-07-09' AND '2014-08-15') AND
      co.treated_by IN (2 , 40)
GROUP BY co.treated_by;

请注意，我还使用MySQL支持的更简单版本替换了total的计算。

MySQL在单个请求中的同一个表中有多个COUNT

2 个答案: