asp.net使用json.net解析数组json

时间:2014-08-09 05:49:53

标签: asp.net json json.net

我写这段代码:

public void ProcessRequest(HttpContext context)
{
    string m_order;

    try
    {
        var jsonSerilizer = new JavaScriptSerializer();
        var jsonString = String.Empty;
        context.Request.InputStream.Position = 0;
        using (var inputStream = new StreamReader(context.Request.InputStream))
        {
            jsonString = inputStream.ReadToEnd();
        }

        List<myClass> tmp = JsonConvert.DeserializeObject<List<myClass>>(jsonString);

        for (int i = 0; i < tmp.Count(); i++)
        {
            File.AppendAllText(@"d:\status\LOL.txt", "tmp["+(i+1)+"].rid=" +tmp[i].r_id  + "\r\n", Encoding.UTF8);

        }

myClass定义为:

public class myClass
{
    public int f_id{get; set; }
    public int r_id { get; set; }
    public int count { get; set; }
    public int c_id { get; set; }
}

当我将JSON字符串从客户端发送到我的服务器时,我的服务器转到HTTP处理程序并返回以下JSON字符串,所有这些都按预期进行。

[
    {
        f_id:100,
        r_id:200,
        count:2,
        c_id=111
    },
    {
        f_id:120,
        r_id:200,
        count:1,
        c_id=111
    }
]

但是当程序遇到这一行时:

List<myClass> tmp = JsonConvert.DeserializeObject<List<myClass>>(jsonString);

我的服务器因以下异常而崩溃。

Newtonsoft.Json.JsonReaderException: Invalid JavaScript property identifier character: =. Path '[0].count', line 2, position 32.
   at Newtonsoft.Json.JsonTextReader.ParseUnquotedProperty()
   at Newtonsoft.Json.JsonTextReader.ParseProperty()
   at Newtonsoft.Json.JsonTextReader.ParseObject()
   at Newtonsoft.Json.JsonTextReader.ReadInternal()
   at Newtonsoft.Json.JsonTextReader.Read()
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.PopulateObject(Object newObject, JsonReader reader, JsonObjectContract contract, JsonProperty member, String id)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateObject(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateValueInternal(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.PopulateList(IList list, JsonReader reader, JsonArrayContract contract, JsonProperty containerProperty, String id)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateList(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, Object existingValue, String id)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateValueInternal(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.Deserialize(JsonReader reader, Type objectType, Boolean checkAdditionalContent)
   at Newtonsoft.Json.JsonSerializer.DeserializeInternal(JsonReader reader, Type objectType)
   at Newtonsoft.Json.JsonConvert.DeserializeObject(String value, Type type, JsonSerializerSettings settings)
   at Newtonsoft.Json.JsonConvert.DeserializeObject[T](String value, JsonSerializerSettings settings)
   at Portal.Get_O.ProcessRequest(HttpContext context)

1 个答案:

答案 0 :(得分:1)

json&#34; c_id = 111&#34;字符串无效。正确的json应始终位于key:value对中。键值应该用冒号(:)分隔。     {         F_ID:100,         R_ID:200,         数:2,         的 C_ID = 111     },     {         F_ID:120,         R_ID:200,         数:1,         的 C_ID = 111     }

正确的json应如下所示:     {         F_ID:100,         R_ID:200,         数:2,         的 C_ID:111     },     {         F_ID:120,         R_ID:200,         数:1,         的 C_ID:111     }

因此,只需验证&#34; context.Request.InputStream&#34;中包含的数据。分析这个问题可能会有所帮助。