在JSON.NET中解析JSON数组

时间:2016-12-26 06:19:15

标签: c# json json.net

我在REST API响应中有JSON对象:

{
    Result:
    [
        {
            "id": 1,
            "id_endpoint": 1,
            "name": "Endpoint 1",
            "description": "Endpoint 1",
            "unit": "mmol",
            "minthreshold": 30,
            "maxthreshold": -15,
            "id_device": 4,
            "value": 7,
            "time": "2016-12-24T21:20:19.000Z",
            "address": "Endpoint 1",
            "id_user": 1
        }, {
            "id": 2,
            "id_endpoint": 1,
            "name": "Endpoint 1",
            "description": "Endpoint 1",
            "unit": "mmol",
            "minthreshold": 30,
            "maxthreshold": -15,
            "id_device": 4,
            "value": 6,
            "time": "2016-12-24T21:20:16.000Z",
            "address": "Endpoint 1",
            "id_user": 1
        }, {
            "id": 3,
            "id_endpoint": 1,
            "name": "Endpoint 1",
            "description": "Endpoint 1",
            "unit": "mmol",
            "minthreshold": 30,
            "maxthreshold": -15,
            "id_device": 4,
            "value": 8,
            "time": "2016-12-24T21:18:38.000Z",
            "address": "Endpoint 1",
            "id_user": 1
        }
    ],
    StatusCode: 200
}

如果出现错误,他们会得到:

{
    Result: null,
    StatusCode: 404
}

我正在使用JSON.NET而且我已经上课 DeviceInfo.cs

public class DeviceInfo
{
    public int DeviceID {get;set;}
    public int EndpointID {get;set;}
    public string DeviceName {get;set;}
    public double MinThreshold {get;set;}
    public double MaxThreshold {get;set;}
    public double CurrentValue {get;set;}
    public DateTime ValueTime {get;set;}
    public string EndpointAddress {get;set;}
    public int IDUser {get;set;}
}

我的问题是如何在JSON对象中解析Result数组并将其存储在DeviceInfo类中?

3 个答案:

答案 0 :(得分:5)

你需要属性帮助Newtonsoft.Json将源映射到你的类。

public class DeviceInfo
{
    [JsonProperty("id")]
    public int DeviceID { get; set; }
    [JsonProperty("id_endpoint")]
    public int EndpointID { get; set; }
    [JsonProperty("name")]
    public string DeviceName { get; set; }
    [JsonProperty("minthreshold")]
    public double MinThreshold { get; set; }
    [JsonProperty("maxthreshold")]
    public double MaxThreshold { get; set; }
    [JsonProperty("value")]
    public double CurrentValue { get; set; }
    [JsonProperty("time")]
    public DateTime ValueTime { get; set; }
    [JsonProperty("address")]
    public string EndpointAddress { get; set; }
    [JsonProperty("id_user")]
    public int IDUser { get; set; }
}

你的json被包裹的外层。

public class RootObject
{
    public List<DeviceInfo> Result { get; set; }
    public int StatusCode { get; set; }
}

最后,您可以使用JsonConvert反序列化您的json。

var result = JsonConvert.DeserializeObject<RootObject>(json);

答案 1 :(得分:0)

您可以使用JsonDeserialize来解析json

var array = JsonConvert.DeserializeObject<List<DeviceInfo>>(str);

答案 2 :(得分:0)

请参阅以下代码:

var response =  JsonConvert.DeserializeObject<Dictionary<string,object>>(JSONstring);

if(response != null && response["StatusCode"] == "200")
{
     List<DeviceInfo> lstResult = JsonConvert.DeserializeObject<List<DeviceInfo>(response["Result"]);
}

我希望这会有所帮助。