Question

我无法获取表单发布变量，然后让我的PDO语句执行删除。我知道变量$得到的[WID]确实在我的表单中存储了正确的值。问题在于将变量从这个表单传递给下面的代码来执行delete语句。我得到的错误是：参数号无效：参数未定义

//这是php / PDO代码：

 if(isset($_POST['remove'])){
 $the_WID = $_POST['WID'];
 echo "here is the WID" . $the_WID;

 $dlt = "DELETE FROM writing WHERE writing.WID = :writing.WID";
 $stmtdlt = $dbh->prepare($dlt);
 $stmtdlt->bindParam(':writing.WID', $the_WID, PDO::PARAM_INT);                                           
 $stmtdlt->execute(); 
 }

//这是表格

<form action="" method="post">
<button type="submit">Delete</button>
<input TYPE="hidden" name="remove" VALUE="<?php $resulting[WID]; ?>">
</form>

Answer 1

$the_WID = $_POST['WID'];应为$the_WID = $_POST['remove'];。
您需要回应您的价值：value="<?php echo $resulting[WID]; ?>"
从the answer to this question开始，您似乎无法在占位符中使用.：

BINDCHR = [：] [a-zA-Z0-9 _] +;

您可以使用字母数字+下划线。

将您的PHP更改为：

if(isset($_POST['remove'])){
    $the_WID = $_POST['remove'];
    echo "here is the WID" . $the_WID;

    $dlt = "DELETE FROM writing WHERE writing.WID = :writingWID";
    $stmtdlt = $dbh->prepare($dlt);
    $stmtdlt->bindParam(':writingWID', $the_WID, PDO::PARAM_INT);                                           
    $stmtdlt->execute(); 
}

和您的HTML表单：

<form action="" method="post">
<button type="submit">Delete</button>
<input type="hidden" name="remove" value="<?php echo $resulting[WID]; ?>">
</form>

无法获取要执行的PDO删除语句

1 个答案: