我有一个pdo块,用于将值插入到我的表中,如下所示
try{
$user = 'root';
$pass = null;
$pdo = new PDO('mysql:host=localhost; dbname=divebay', $user, $pass);
$name = $_POST['name'];
$desc = $_POST['description'];
$cond = $_POST['condGroup'];
$sprice = $_POST['sprice'];
$iprice = $_POST['iprice'];
$incprice = $_POST['incprice'];
$duration = $_POST['duration'];
$img = $_POST['img'];
$owner = $_SESSION['username'];
$valid = "set";
$stmt2 = $pdo->prepare("SELECT * FROM auction WHERE ID = :id");
$stmt2->bindParam(":id", $random, PDO::PARAM_INT);
while(isset($valid)){
$random = rand(100000,999999);
$stmt2->execute();
if(!$stmt2->fetch(PDO::FETCH_ASSOC)){
unset($valid);
}
}
$timestamp = time() + ($duration * 24 * 60 * 60);
$stmt = $pdo->prepare("INSERT INTO auction(ID, name, owner, holder, sprice, iprice, incprice, etime, img, condition, description)
VALUES (:id, :name, :owner, :holder, :sprice, :iprice, :incprice:, :etime, :img, :condition, :description");
$stmt->bindParam(':id', $random, PDO::PARAM_INT);
$stmt->bindParam(':name', $name, PDO::PARAM_STR);
$stmt->bindParam(':owner', $owner, PDO::PARAM_STR);
$stmt->bindParam(':holder', $owner, PDO::PARAM_STR);
$stmt->bindParam(':iprice', $iprice, PDO::PARAM_STR);
$stmt->bindParam(':sprice', $sprice, PDO::PARAM_STR);
$stmt->bindParam(':incprice', $incprice, PDO::PARAM_STR);
$stmt->bindParam(':etime', $timestamp, PDO::PARAM_INT);
$stmt->bindParam(':img', $img, PDO::PARAM_STR);
$stmt->bindParam(':condition', $condition, PDO::PARAM_STR);
$stmt->bindParam(':description', $description, PDO::PARAM_STR);
if($stmt->execute()){
$worked ="yes";
}
}catch(PDOException $e){
echo $e->getMessage();
}
我不知道为什么这个语句不会执行,在脚本运行时没有设置$ working变量。所有数据库列名和数据类型都已按原样检查正确。我从来没有遇到过直到现在才执行的声明的问题。怎么了?我该如何调试呢?
答案 0 :(得分:4)
如果使用错误模式设置数据库连接异常,如果您的语句出现问题,PDO将抛出异常。我还看到你正在使用MySQL驱动程序进行PDO。如果这样做,您应该始终禁用模拟的预准备语句。所以我会写下你的连接如下(注意我也设置了编码):
$pdo = new PDO('mysql:host=localhost; dbname=divebay;charset=utf8', $user, $pass);
$pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
有关详细信息,请参阅this post。
完成此操作后,您将看到您的陈述错误。您在声明的最后有一个)
:
$stmt = $pdo->prepare("INSERT INTO auction(ID, name, owner, holder, sprice, iprice, incprice, etime, img, condition, description)
VALUES (:id, :name, :owner, :holder, :sprice, :iprice, :incprice:, :etime, :img, :condition, :description)");
^
答案 1 :(得分:1)
修改此行:
$stmt = $pdo->prepare("INSERT INTO auction(ID, name, owner, holder, sprice, iprice, incprice, etime, img, condition, description)
VALUES (:id, :name, :owner, :holder, :sprice, :iprice, :incprice:, :etime, :img, :condition, :description");
要
$stmt = $pdo->prepare("INSERT INTO auction(ID, name, owner, holder, sprice, iprice, incprice, etime, img, condition, description)
VALUES (:id, :name, :owner, :holder, :sprice, :iprice, :incprice:, :etime, :img, :condition, :description)");
差异在于最后的)
。
告诉我它现在是否有效。