Question

我很确定我过于复杂，但我不知道如何以另一种方式做到这一点。

我想创建一个数组，其中包含一个月中一周的数字作为键，以及本周的日期作为值。

我使用此功能来获取一周的所有日子：

public function getDaysOfWeek($year, $month, $day)
{
    $firstMondayThisWeek = new DateTime($year . '/' . $month . '/' . $day, new DateTimeZone("Europe/Berlin"));
    $firstMondayThisWeek->modify('tomorrow');
    $firstMondayThisWeek->modify('last Monday');

    $nextSevenDays = new DatePeriod(
        $firstMondayThisWeek,
        DateInterval::createFromDateString('+1 day'),
        6
    );

    return $nextSevenDays;
}

这个函数构建数组：

public function getWeekAndDays($year, $month)
{
    $weeksInMonth = Carbon::createFromDate($year, $month)->endOfMonth()->weekOfMonth;   
    $weekBegin = Carbon::createFromDate($year, $month)->startOfMonth();

    $weeks = [];

    for($i=1; $i<=$weeksInMonth; $i++)
    {
        $collection = new \stdClass();
        $collection->week = $i;
        $collection->days = $this->getDaysOfWeek($year, $month, $weekBegin->day);

        $weekBegin->addWeek(0);

        $weeks[] = $collection;
    }

    return $weeks;
}

除了2月份之外的所有月份，我都会有5周的时间。对于2月份，我有4周的时间，所以我无法保存月份重叠的日子。

我在这里完全错了吗？有什么方法可以解决这个问题？

Answer 1

我的朋友感觉到你的痛苦，使用日历数据很烦人。这是我之前写过的一个函数，它构建了一个数周和数天的数组，以数月分隔。它不是最干净的代码，但它有效。

它将从您传递到$today的日期开始，作为＆＃34; Y-m-d＆＃34; （或默认为当前日期），然后返回当前月的第一周，从那里开始，然后继续$scheduleMonths个月建立一个按月索引，然后按周索引的数组。

这里有点难以解释，但它是自包含的，所以您可以将其复制/粘贴到您的代码中，然后dd()输出以查看它的外观和如果它适合你，并从那里修改它。您可能需要调整一些格式，因为它是针对我的特定用例而做的，但业务逻辑应该是合理的。

您应该能够从输出中提取给定月份的周数（因此，如果您需要的话，只要您确认它正常工作，就可以简化此操作）。

public function getWeeks($today = null, $scheduleMonths = 6) {

    $today = !is_null($today) ? Carbon::createFromFormat('Y-m-d',$today) : Carbon::now();

    $startDate = Carbon::instance($today)->startOfMonth()->startOfWeek()->subDay(); // start on Sunday
    $endDate = Carbon::instance($startDate)->addMonths($scheduleMonths)->endOfMonth();
    $endDate->addDays(6 - $endDate->dayOfWeek);

    $epoch = Carbon::createFromTimestamp(0);
    $firstDay = $epoch->diffInDays($startDate);
    $lastDay = $epoch->diffInDays($endDate);

    $week=0;
    $monthNum = $today->month;
    $yearNum = $today->year;
    $prevDay = null;
    $theDay = $startDate;
    $prevMonth = $monthNum;

    $data = array();

    while ($firstDay < $lastDay) {

        if (($theDay->dayOfWeek == Carbon::SUNDAY) && (($theDay->month > $monthNum) || ($theDay->month == 1))) $monthNum = $theDay->month;
        if ($prevMonth > $monthNum) $yearNum++;

        $theMonth = Carbon::createFromFormat("Y-m-d",$yearNum."-".$monthNum."-01")->format('F Y');

        if (!array_key_exists($theMonth,$data)) $data[$theMonth] = array();
        if (!array_key_exists($week,$data[$theMonth])) $data[$theMonth][$week] = array(
            'day_range' => '',
        );

        if ($theDay->dayOfWeek == Carbon::SUNDAY) $data[$theMonth][$week]['day_range'] = sprintf("%d-",$theDay->day);
        if ($theDay->dayOfWeek == Carbon::SATURDAY) $data[$theMonth][$week]['day_range'] .= sprintf("%d",$theDay->day);

        $firstDay++;
        if ($theDay->dayOfWeek == Carbon::SATURDAY) $week++;
        $theDay = $theDay->copy()->addDay();
        $prevMonth = $monthNum;
    }

    $totalWeeks = $week;

    return array(
        'startDate' => $startDate,
        'endDate' => $endDate,
        'totalWeeks' => $totalWeeks,
        'schedule' => $data,
    );

}

我希望这可以帮助你至少开始！

Answer 2

这样的东西？

function weekOfMonth($date) {

    $firstOfMonth = strtotime(date("Y-m-01", $date));
    $lastWeekNumber = (int)date("W", $date);
    $firstWeekNumber = (int)date("W", $firstOfMonth);
    if (12 === (int)date("m", $date)) {
        if (1 == $lastWeekNumber) {
            $lastWeekNumber = (int)date("W", ($date - (7*24*60*60))) + 1;
        }
    } elseif (1 === (int)date("m", $date) and 1 < $firstWeekNumber) {
        $firstWeekNumber = 0;
    }
    return $lastWeekNumber - $firstWeekNumber + 1;
}

function weeks($month, $year){
    $lastday = date("t", mktime(0, 0, 0, $month, 1, $year));
    return weekOfMonth(strtotime($year.'-'.$month.'-'.$lastday));
}

$result = [];

for ($year = 2017; $year < 2020; $year++){
    for ($month = 1; $month < 13; $month++) {
        $numOfWeeks = weeks($month, $year);
        $result[$year][$month]['numOfWeeks'] = $numOfWeeks;
        $daysInFirstWeek = 8 - date('N', strtotime($year.'-'.$month.'-01'));
        $result[$year][$month]['daysPerWeek']['week_1'] = $daysInFirstWeek;
        $startDay = date('d', strtotime('next Monday', strtotime($year.'-'.$month.'-01')));
        for ($i = 1; $i < ($numOfWeeks - 1); $i++) {
            $startDay += 7;
            $result[$year][$month]['daysPerWeek']['week_'.($i+1)] = 7;
        }

        //last week
        $result[$year][$month]['daysPerWeek']['week_'.($i+1)] = date('t', strtotime($year.'-'.$month.'-01')) - $startDay + 1;
    }
}

echo json_encode($result)."\n";

获取一个月内的周数和相应的天数

2 个答案: