我正在尝试使用时刻js计算一个月内的周数。但是我在2015年5月和2015年8月的几个月里得到了错误的结果。
我正在使用此代码。
var start = moment().startOf('month').format('DD');
var end = moment().endOf('month').format('DD');
var weeks = (end-start+1)/7;
weeks = Math.ceil(weeks);
在JS中是否有任何预建方法可以获得周数。
答案 0 :(得分：3)
我已经创建了这个要点，可以查找给定月份和年份的所有周数。通过计算calendar的长度，您将知道周数。
https://gist.github.com/guillaumepiot/095b5e02b4ca22680a50
# year and month are variables
year = 2015
month = 7 # August (0 indexed)
startDate = moment([year, month])
# Get the first and last day of the month
firstDay = moment(startDate).startOf('month')
endDay = moment(startDate).endOf('month')
# Create a range for the month we can iterate through
monthRange = moment.range(firstDay, endDay)
# Get all the weeks during the current month
weeks = []
monthRange.by('days', (moment)->
if moment.week() not in weeks
weeks.push(moment.week())
)
# Create a range for each week
calendar = []
for week in weeks
# Create a range for that week between 1st and 7th day
firstWeekDay = moment().week(week).day(1)
lastWeekDay = moment().week(week).day(7)
weekRange = moment.range(firstWeekDay, lastWeekDay)
# Add to the calendar
calendar.push(weekRange)
console.log calendar
答案 1 :(得分：2)
var move = d3.behavior.drag()
.on("dragstart", function() {
d3.event.sourceEvent.stopPropagation();
});
答案 2 :(得分：2)
可以使用原始javascript轻松完成：
function getNumWeeksForMonth(year,month){
date = new Date(year,month-1,1);
day = date.getDay();
numDaysInMonth = new Date(year, month, 0).getDate();
return Math.ceil((numDaysInMonth + day) / 7);
}
您获得第一天的日期索引，将其添加到补偿第一周丢失天数的天数，除以7并使用ceil为下周最简单的溢出添加1
答案 3 :(得分：1)
这里是javaScript版本
var year = 2021
var month = 6
var startDate = moment([year, month])
//Get the first and last day of the month
var firstDay = moment(startDate).startOf('month')
var endDay = moment(startDate).endOf('month')
//Create a range for the month we can iterate through
var monthRange = moment.range(firstDay, endDay)
//Get all the weeks during the current month
var weeks = []
var indexOf = [].indexOf;
monthRange.by('days', function (moment) {
var ref;
if (ref = moment.week(), indexOf.call(weeks, ref) < 0) {
return weeks.push(moment.week());
}
});
var calendar, firstWeekDay, i, lastWeekDay, len, week, weekRange;
calendar = [];
for (i = 0, len = weeks.length; i < len; i++) {
week = weeks[i];
// Create a range for that week between 1st and 7th day
firstWeekDay = moment().week(week).day(0);
lastWeekDay = moment().week(week).day(6);
weekRange = moment.range(firstWeekDay, lastWeekDay);
// Add to the calendar
calendar.push(weekRange);
}
答案 4 :(得分：0)
这是最好的出路，效果很好
moment.relativeTime.dd = function (number) {
// round to the closest number of weeks
var weeks = Math.round(number / 7);
if (number < 7) {
// if less than a week, use days
return number + " days";
} else {
// pluralize weeks
return weeks + " week" + (weeks === 1 ? "" : "s");
}
}
答案 5 :(得分：0)
calcWeeksInMonth(date) {
const dateFirst = moment(date).date(1)
const dateLast = moment(date).date(date.daysInMonth())
const startWeek = dateFirst.week()
const endWeek = dateLast.week()
if (endWeek < startWeek) {
return dateFirst.weeksInYear() - startWeek + 1 + endWeek
} else {
return endWeek - startWeek + 1
}
}
这似乎输出正确的结果，如果我错过了某些事情，欢迎反馈！
答案 6 :(得分：0)
它使用'moment.js'显示一个月中的几周列表。
它是用打字稿写的，角度为6+。
使用“ npm i moment”安装时刻
在ts文件中。
weeks_in_month() {
let year = 2019; // change year
let month = 4; // change month here
let startDate = moment([year, month - 1])
let endDate = moment(startDate).endOf('month');
var dates = [];
var weeks = [];
var per_week = [];
var difference = endDate.diff(startDate, 'days');
per_week.push(startDate.toDate())
let index = 0;
let last_week = false;
while (startDate.add(1, 'days').diff(endDate) < 0) {
if (startDate.day() != 0) {
per_week.push(startDate.toDate())
}
else {
if ((startDate.clone().add(7, 'days').month() == (month - 1))) {
weeks.push(per_week)
per_week = []
per_week.push(startDate.toDate())
}
else if (Math.abs(index - difference) > 0) {
if (!last_week) {
weeks.push(per_week);
per_week = [];
}
last_week = true;
per_week.push(startDate.toDate());
}
}
index += 1;
if ((last_week == true && Math.abs(index - difference) == 0) ||
(Math.abs(index - difference) == 0 && per_week.length == 1)) {
weeks.push(per_week)
}
dates.push(startDate.clone().toDate());
}
console.log(weeks);
}
结果：
日期时刻数组。
[Array(6), Array(7), Array(7), Array(7), Array(3)]
0: (6) [Mon Apr 01 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 02 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 03 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 04 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 05 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 06 2019 00:00:00 GMT+0530 (India Standard Time)]
1: (7) [Sun Apr 07 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 08 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 09 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 10 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 11 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 12 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 13 2019 00:00:00 GMT+0530 (India Standard Time)]
2: (7) [Sun Apr 14 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 15 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 16 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 17 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 18 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 19 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 20 2019 00:00:00 GMT+0530 (India Standard Time)]
3: (7) [Sun Apr 21 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 22 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 23 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 24 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 25 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 26 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 27 2019 00:00:00 GMT+0530 (India Standard Time)]
4: (3) [Sun Apr 28 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 29 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 30 2019 00:00:00 GMT+0530 (India Standard Time)]
答案 7 :(得分：0)
我还没有看到在所有情况下都可行的解决方案。我尝试了所有这些方法，但是它们都以一种或另一种方式存在缺陷。同上几个moment.js github线程。这是我的裂缝：
getNumberOfWeeksInMonth = (momentDate) => {
const monthStartWeekNumber = momentDate.startOf('month').week();
const distinctWeeks = {
[monthStartWeekNumber]: true
};
let startOfMonth = momentDate.clone().startOf('month');
let endOfMonth = momentDate.clone().endOf('month');
// this is an 'inclusive' range -> iterates through all days of a month
for (let day = startOfMonth.clone(); !day.isAfter(endOfMonth); day.add(1, 'days')) {
distinctWeeks[day.week()] = true
}
return Object.keys(distinctWeeks).length;
}
答案 8 :(得分：0)
function weeksInMonth(date = null){
let firstDay = moment(date).startOf('month');
let endDay = moment(date).endOf('month');
let weeks = [];
for (let i = firstDay.week(); i <= endDay.week(); i++){
weeks.push(i)
}
return weeks;
}
答案 9 :(得分：0)
答案 10 :(得分：0)
把它扔进去
import moment from "moment";
export const calcWeeksInMonth = date => {
let weekMonthEnds = moment(date)
.date(moment(date).daysInMonth())
.week();
let weekMonthStarts = moment(date)
.date(1)
.week();
return weekMonthEnds < weekMonthStarts
? moment(date).isoWeeksInYear() - weekMonthStarts + 1
: weekMonthEnds - weekMonthStarts + 1;
};
答案 11 :(得分：0)
var month = moment().month();
var startOfMonth = month.startOf("month");
var endOfMonth = month.endOf("month");
var startWeekNumber = startOfMonth.isoWeek();
var endWeekNumber = endOfMonth.isoWeek();
var numberOfWeeks = (endWeekNumber - startWeekNumber + 1);
console.log(numberOfWeeks);
答案 12 :(得分：0)
如果您有 selectedDate 值，可以让您有机会检测现在哪个月处于活动状态：
private calculateNumberOfWeeks(): number {
const end = moment(this.selectedDate).endOf('month');
const startDay = moment(this.selectedDate)
.startOf('month')
.day();
const endDay = end.day();
const endDate = end.date();
return (startDay - 1 + endDate + (endDay === 0 ? 0 : 7 - endDay)) / 7;
}