Question

我已经启动了这个，只有名称和电子邮件字段，查询确实成功运行，因为它工作正常我添加了更多字段更新代码。但这次它没有用，带我到同一页面，没有给我任何错误。

<?php 

require "config.php";

if(isset($_POST['name']) && isset($_POST['address']) && isset($_POST['city']) && isset($_POST['postalcode']) && isset($_POST['country']) && isset($_POST['email']) && isset($_POST['datepicker']) && isset($_POST['phone'])) {
  $name = $_POST['name'];
  $address = $_POST['address'];
  $city = $_POST['city'];
  $postalcode = $_POST['postalcode'];
  $country = $_POST['country'];
  $email = $_POST['email']; 
  $birthday = $_POST['datepicker'];
  $phone = $_POST['phone'];
  $IP = $_SERVER['REMOTE_ADDR'];
  $date = date('Y-m-d H:i:s');

  if(!empty($name) && !empty($address) && !empty($city) && !empty($postalcode) && !empty($country) && !empty($email) && !empty($birthday) && !empty($phone)) {
    $query = "INSERT INTO `users` (name, address, city, postalcode, country, email, birthday, phone, IP, date) VALUES ('$name', '$address', '$city', '$postalcode', '$country', '$email', '$birthday' '$phone', '$IP', '$date')";

    $result = mysql_query($query);

                 if($result) {
      echo "Registered Successfully";
    } else {
      echo "You're required to fill in all the fields.";
    }
  } 
}

 ?>

<form action="join.php" method="POST">

<p> <label for="name">Name:</label>
<input type="text" name="name" > </p>

<p> <label for="address">Address:</label>
<input type="text" name="address" > </p>

<p> <label for="city">City:</label>
<input type="text" name="city" > </p>

<p> <label for="postalcode">Postal Code:</label>
<input type="text" name="postalcode" > </p>

<p> <label for="country">Country:</label>
<input type="text" name="country" > </p>

<p> <label for="email">Email:</label>
<input type="text" name="email" > </p>

<p> <label for="birthday">Birthday:</label>
<input type="text" name="birthday" > </p>

<p> <label for="phone">Phone:</label>
<input type="text" name="phone" > </p>

<input type="submit" value="order">

 </form>

我已在此处粘贴代码：http://codepad.org/BuRFV276

Answer 1

您没有任何名为＆＃39; datepicker＆＃39;。

的字段

只需将所有$_POST['datepicker']替换为$_POST['birthday']

并且插入查询中存在语法错误。您错过了$ birthday和$ phone

之间的逗号

不要使用mysql_*因为所有mysql_*函数都已弃用，而是使用mysqli或PDO。

Answer 2

您在$birthday和$phone变量之间错过了逗号 -

'$birthday' '$phone',
//         ^ right there

无法在PHP和MySQL中运行查询

2 个答案: