Question

我试图在php中运行此代码，但不打印任何内容。

我的数据库不为空。

Convert.ToDecimal

EX：我在我的数据库中记录了这个用户用户=穆赫辛链接：

http://test.kholaseketab.ir/Update.php

Answer 1

您正在混合面向对象和程序样式查询。

<?php
$dbname = "mytest";
$servername = "***";
$username = "mohsen";
$passwords = "****";
// Create connection
$conn = new mysqli($servername, $username, $passwords, $dbname);
// Check connection
if ($conn->connect_error) {
 die("Connection failed: " . $conn->connect_error);
}
$User=$_POST['username'];
$sql="SELECT * FROM Money WHERE Debtor='$User' OR Creditor='$User'  ";
$result = $conn->query($sql);

//
while($field = $result->fetch_object())
{

print $field->Debtor."|";
print $field->Creditor."|";
print $field->Cost."|";
print $field->Status."|"."\n";

}
$conn->close();
?>

Answer 2

<?php
   $dbname = "mytest";
   $servername = "***";
   $username = "mohsen";
   $passwords = "****";

   // Create connection
  $conn = new mysqli($servername, $username, $passwords, $dbname);

  // Check connection
  if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
  }

  $User=$_POST['username'];
  $sql="SELECT * FROM Money WHERE Debtor='$User' OR Creditor='$User'  ";
  $result = $conn->query($sql);

  while($field=$result->fetch_assoc())
  {
     print $field["Debtor"]."|";
     print $field["Creditor"]."|";
     print $field["Cost"]."|";
     print $field["Status"]."|"."\n";
  }

  $conn->close();
?>

为什么我无法运行此查询？

2 个答案: