Question

我是android新手，我做了一个活动，我必须发布一些参数来进行api调用并得到响应，我必须传递一些参数追加到请求url和其他像Json格式，请告诉我我该怎么办，我的示例网址请求如下：

http://dev.abctest.com/api/v1/book?customer_firstname=jigar&customer_lastname=jims&customer_mobile=9033309333&customer_email=jigar@epagestore.com&source_country=India&number_of_travellers=15

和json体中的其他参数如下：

{

    "destinations": [
        {
            "city_id": 1,
            "start_date": "2014/08/28",
            "end_date": "2014/09/30"
        },
        {
            "city_id": 5,
            "start_date": "2014/08/10",
            "end_date": "2014/09/03"
        }
    ]
}

Answer 1

将JsonParserHelper用作Utility类。每当你点击网址时。

a。）上课并将你的网址分开假设App_WebServiceUrls

public class App_WebServiceUrls {

public static String GetDetails ="http://dev.abctest.com/api/v1/book";

}

2.现在打电话给webservice / Web Api。单独调用api调用或使用Asynctasks 所以要避免使用NetworkOnMainThredException。

new Thread(new Runnable() {

            @Override
            public void run() {
                // TODO Auto-generated method stub

                // Add your data
            List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>();

                nameValuePair.add(new BasicNameValuePair(customer_firstname, "Deepak"));
                nameValuePair.add(new BasicNameValuePair(customer_lastname, "Panwar"));


JSONObject json = null;

        try {

            json = new JSONObject();

    json = JsonParserHelper.makeHttpRequest(
                    App_WebServiceUrls.CompanyDivisions, "GET", nameValuePair);

            Log.d("Division List Response:", "" + json);

            if (json != null) {
}else
{

    /**To print tost on ui thread**/
    runOnUiThread(new Runnable() {

            @Override
            public void run() {
                // TODO Auto-generated method stub

              /**Write Toast here**/

            }
        });

} catch (JSONException e) {
            e.printStackTrace();
        }


            }
        }).start();

/ 助手类 /

public class JsonParserHelper {

    static InputStream is = null;

    static JSONObject jObj = null;

    static JSONArray jArr = null;

    static String json = "";

    public static JSONObject makeHttpRequest(String url, String method,

    List<NameValuePair> params) {

        try {

            if (method == "POST") {

                DefaultHttpClient httpClient = new DefaultHttpClient();

                String paramString = URLEncodedUtils.format(params, "utf-8");
                url += "?" + paramString;

                Log.v("Urltocheck", "" + url);

                HttpPost httpPost = new HttpPost(url);
                httpPost.setEntity(new UrlEncodedFormEntity(params, "utf-8"));
                HttpResponse httpResponse = httpClient.execute(httpPost);
                HttpEntity httpEntity = httpResponse.getEntity();

                is = httpEntity.getContent();

            } else if (method == "GET") {
                // request method is GET
                DefaultHttpClient httpClient = new DefaultHttpClient();

                String paramString = URLEncodedUtils.format(params, "utf-8");
                url += "?" + paramString;

                Log.v("Urltocheck", "" + url);

                HttpGet httpGet = new HttpGet(url);
                HttpResponse httpResponse = httpClient.execute(httpGet);
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();
            }

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            // jArr = new JSONArray(json);

            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

        // return JSON String (Array)
        // return jArr;

        return jObj;

    }

}

Answer 2

首先，您需要将网址字段附加到基本网址。然后，如果有任何字段，您可以添加可选字段。然后将您的数据作为HttpPost中的实体，其中url将是处理后获得的url。

请尝试以下操作：

要调用的父方法。

public void request(String baseUrl,List<NameValuePair> urlFields, List<NameValuePair> formData,List<NameValuePair> optionalData ){

// Append params to the URL 
if (urlFields != null)
    baseUrl = baseUrl + getUrlPathForGet(urlFields);

// adds Optional fields to the Url
if (optional != null)
    baseUrl = baseUrl + "?" + URLEncodedUtils.format(optionalData, "utf-8");

postData(baseUrl,formData);

}

它会将url参数附加到基本网址

private String getUrlPathForGet(List<NameValuePair> urlFields) {

String path = "";

if (urlFields != null) {

    for (NameValuePair pair : urlFields) {
    path = path + "/" + pair.getValue();
    }
}

return path;
}

使用修改后的网址将表单数据作为实体添加到HttpPost对象。

public void postData(String baseUrl,List<NameValuePair> formData) {

// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
// pass the url as parameter and create HttpPost object.
HttpPost post = new HttpPost(baseUrl);

// Add header information for your request - no need to create 
// BasicNameValuePair() and Arraylist.
post.setHeader("Authorization", "Bearer " + token);
post.setHeader("Content-Type", "application/json");
post.setHeader("Cache-Control", "no-cache");    

try {       

// pass the content as follows:
post.setEntity(new UrlEncodedFormEntity(formData,
                    HTTP.UTF_8));

// Execute HTTP Post Request
HttpResponse response = httpclient.execute(post);

// TODO: Process your response as you would like.

} catch (IOException e) {
    // TODO Auto-generated catch block
}
}

如何在android中的requestUrl和其他JSON请求中传递一半参数？

2 个答案: