使用此表单中的嵌套参数传递json的正确代码是什么
{"method":"startSession",
"params": [ "email": "testmail@test.it",
"password": "1234",
"stayLogged": "1",
"idClient": "ANDROID"
]
}
到接收RPC的Web服务URL
网络服务代码是
@Webservice(paramNames = {"email", "password", "stayLogged", "idClient"},
public Response startSession(String email, String password, Boolean stayLogged, String idClient) throws Exception {
boolean rC = stayLogged != null && stayLogged.booleanValue();
UserService us = new UserService();
User u = us.getUsersernamePassword(email, password);
if (u == null || u.getActive() != null && !u.getActive().booleanValue()) {
return ErrorResponse.getAccessDenied(id, logger);
}
InfoSession is = null;
String newKey = null;
while (newKey == null) {
newKey = UserService.md5(Math.random() + " " + new Date().getTime());
if (SessionManager.get(newKey) != null) {
newKey = null;
} else {
is = new InfoSession(u, rC, newKey);
if (idClient != null && idClient.toUpperCase().equals("ANDROID")) {
is.setClient("ANDROID");
}
SessionManager.add(newKey, is);
}
}
logger.log(Level.INFO, "New session started: " + newKey + " - User: " + u.getEmail());
return new Response(new InfoSessionJson(newKey, is), null, id);
}
答案 0 :(得分:2)
我将假设您使用的是json-rpc 1.0,因为您的请求中没有版本指示器。
首先,您错过了“id”,因此请将其添加到请求中。
现在,您可以尝试三种不同的方法。
1)如果要设置名称和值对,则需要使用对象{}而不是array []。 像:
{"method":"startSession",
"params": { "email": "testmail@test.it",
"password": "1234",
"stayLogged": "1",
"idClient": "ANDROID"
},
"id":100
}
2)如果您的json反序列化器需要数组语法[],那么您可能需要将对象{}包装在[]中,如:
{"method":"startSession",
"params": [{ "email": "testmail@test.it",
"password": "1234",
"stayLogged": "1",
"idClient": "ANDROID"
}],
"id":101
}
3)最后,您还可以尝试在数组中使用位置参数:
{"method":"startSession",
"params": [ "testmail@test.it",
"1234",
"1",
"ANDROID"
],
"id":102
}
希望有所帮助。