我在这里展示了三个链接表的(人工)示例: ParentA,ChildA 和 ChildAA 。 ChildA 通过外键与 ParentA 的主键(PK)相关, ChildAA 与 ChildA <中的相同键相关/ em>的。通过这种方式, ChildAA 链接到 ParentA 的主键。我希望当我对 ParentA PK进行更改时,此更改会传播回相应的 ChildAA 的属性,但事实并非如此。
提前致谢!
(如果之前已经回答或记录过,我很抱歉,我真的找不到任何东西。)
守则:
from sqlalchemy import *
from sqlalchemy import orm
from sqlalchemy.ext.declarative import declarative_base
Base = declarative_base()
class ParentA(Base):
__tablename__ = 'tbl_parentA'
pid = Column(Integer, primary_key=True)
childA = orm.relationship("ChildA", passive_updates=False, backref='parentA')
class ChildA(Base):
__tablename__ = 'tbl_childA'
attrib1 = Column(String, nullable=True)
parentA_id = Column(Integer, ForeignKey(ParentA.pid), primary_key=True)
childAA = orm.relationship("ChildAA", passive_updates=False, backref="childA")
# This class is related to Parents through ChildA
class ChildAA(Base):
__tablename__ = 'tbl_childAA'
cid = Column(Integer, primary_key=True)
attrib1 = Column(String, nullable=True)
parentA_id = Column(Integer, ForeignKey(ChildA.parentA_id))
def clear_db(db):
tmp = db.echo
db.echo = False
metadata = MetaData(bind=db)
metadata.reflect(db)
for table in reversed(metadata.sorted_tables):
table.drop(db)
metadata.clear()
db.echo = tmp
if __name__ == '__main__':
# SQLite Connection
db = create_engine('sqlite:///linked_updates.db')
# db.echo = True
# Initalize Objects
pa1 = ParentA()
ca1 = ChildA(attrib1='ca1 str')
caa1= ChildAA(attrib1='caa1 str')
# Assign a parent to ChildA
ca1.parentA = pa1
# Assign a parent to ChildAA
caa1.childA = ca1
# Initialize clean DB & session
clear_db(db)
Base.metadata.create_all(db)
session = orm.create_session(db)
# Write to DB
session.add_all([pa1, ca1, caa1])
session.flush()
print 'After flush, we have: ', caa1.parentA_id, '==', caa1.childA.parentA_id
# Induce change, check propagation
pa1.pid = 2
session.flush()
print 'I expect: ', caa1.parentA_id, '==', caa1.childA.parentA_id
print 'END'