Question

我正在尝试创建跨越3个表的关系，但我无法弄清楚语法。

我有3个表TableA，TableB和TableC，而我正在尝试建模的关系是：

TableA.my_relationship = relationship(
    'TableC',
    primaryjoin='and_(TableA.fk == TableB.pk, TableB.fk == TableC.pk)',
    viewonly=True
)

因此，在TableA的实例上，我可以instance_of_a.my_relationship获取与TableC间接关联的instance_of_a记录

Answer 1

from sqlalchemy import *
from sqlalchemy.orm import *
from sqlalchemy.ext.declarative import declarative_base

Base = declarative_base()

class A(Base):
    __tablename__ = 'a'

    id = Column(Integer, primary_key=True)
    b_id = Column(Integer, ForeignKey('b.id'))

    # method one - put everything into primaryjoin.
    # will work for simple lazy loads but for eager loads the ORM
    # will fail to build up the FROM to correctly include B
    cs = relationship("C",
                # C.id is "foreign" because there can be many C.ids for one A.id
                # B.id is "remote", it sort of means "this is where the stuff
                # starts that's not directly part of the A side"
                primaryjoin="and_(A.b_id == remote(B.id), foreign(C.id) == B.c_id)",
                viewonly=True)

    # method two - split out the middle table into "secondary".
    # note 'b' is the table name in metadata.
    # this method will work better, as the ORM can also handle 
    # eager loading with this one.
    c_via_secondary = relationship("C", secondary="b",
                        primaryjoin="A.b_id == B.id", secondaryjoin="C.id == B.c_id",
                        viewonly=True)
class B(Base):
    __tablename__ = 'b'

    id = Column(Integer, primary_key=True)
    c_id = Column(Integer, ForeignKey('c.id'))

class C(Base):
    __tablename__ = 'c'
    id = Column(Integer, primary_key=True)

e = create_engine("sqlite://", echo=True)
Base.metadata.create_all(e)

sess = Session(e)

sess.add(C(id=1))
sess.flush()
sess.add(B(id=1, c_id=1))
sess.flush()
sess.add(A(b_id=1))
sess.flush()

a1 = sess.query(A).first()
print(a1.cs)

print(a1.c_via_secondary)

跨多个表的SQLAlchemy关系

1 个答案: