Question

我正在使用LibGdx在Eclipse中编写一个应用程序，用于具有两个屏幕的游戏。还有一个Question类，它有两个实例变量是Music对象，两个是Strings。第一个屏幕获取对Question对象的引用，并播放问题的Music实例以及包含答案且没有问题的Music实例。但是，当调用第二个屏幕时，对此Question对象的引用将传递到第二个屏幕，但Music对象（从Question中获取）都不再播放。我知道问题被传递到第二个屏幕，因为第二个屏幕可以访问问题的实例变量，这些变量是字符串而不是音乐。这个问题只能在Android上运行时观察到，当我运行桌面项目时，一切正常。这是问题类

public class QuestionClothsType {
    private int ID;
    private String question;
    private Music questionVoice;
    private String answer;
    private Music answerVoice;
    private String colourAnswer;


public QuestionClothsType(int anID, String aQuestion, Music aVoice, String anAnswer, Music     anAnswerVoice, String aColourAnswer){
        this.ID = anID;
        this.question = aQuestion;
        this.questionVoice = aVoice;
        this.answer = anAnswer;
        this.answerVoice = anAnswerVoice;
        this.colourAnswer = aColourAnswer;
    }

    public int getID(){
        return this.ID;
    }
    public Music getQuestionVoice() {
        return this.questionVoice;
    }
    public String getAnswer(){
        return this.answer;
    }
    public Music getAnswerVoice() {
        return this.answerVoice;
    }
    public String getColourAnswer(){
        return this.colourAnswer;
    }
}

这是第二个屏幕的相关部分：

….
Music applause;
Music voiceItem;
Music voiceItem2;
Music voiceItem3;
private QuestionClothsType passedQuestion;
….
public ItemsScreen(Room room, ItemType aType, QuestionClothsType aQuestion){

this.passedQuestion = aQuestion;
voiceItem = passedQuestion.getQuestionVoice();
voiceItem2 = passedQuestion.getQuestionVoice();
voiceItem3 = passedQuestion.getAnswerVoice();
…
private void checkAnswer(int answer2) {
….
if (answerColour.equals(passedQuestion.getColourAnswer())){
        System.out.println("right. the answer was " + passedQuestion.getAnswer());
        applause.play();
        applause.setOnCompletionListener(new OnCompletionListener(){
        @Override
            public void onCompletion(Music aMusic){
                dispose();
                roomGame.setScreen(new ChestOfDrawersScreen(roomGame));

            }
        }
        );

        }

    else{
        System.out.println("wwrong. the answer was " + passedQuestion.getAnswer());
        mistake.play();
        mistake.setOnCompletionListener(new OnCompletionListener(){
            @Override
            public void onCompletion(Music aMusic){
                voiceItem2.play();  
            }
        }
        );          
        }

}
….
@Override
public void show() {
    voiceItem.play();
}

在Android上都没有播放voiceItem和voiceItem2（两者都是从passQuestion.getQuestionVoice（）获得的），而是System.out.println（＆＃34; wwrong。回答是＆＃34; + passedQuestion.getAnswer（））;打印出来，它在桌面上运行良好。

感谢您的帮助。卡洛塔

Answer 1

我认为您应该为资源声明另一个类。这种情况正在发生，因为Android设备的资源比台式机低，因此可能无法及时加载所需的资源。声明另一个名为Resources的类或任何你喜欢的类。并在其中做这样的事情。

    public class Resources {
      public static Music myMusic1;
      public static Music myMusic2;
      public static Music myMusic3;

      public Resources() {}

      public static void load() {
         myMusic1 = Gdx.audio.newMusic(Gdx.files.internal("data/mymusic1.mp3"));
         myMusic2 = Gdx.audio.newMusic(Gdx.files.internal("data/mymusic2.mp3"));
         myMusic3 = Gdx.audio.newMusic(Gdx.files.internal("data/mymusic3.wav"));
      }
    }

现在在你的主Game类中调用这个方法。

    public class MyGame extends Game{
      @Override
      public void create() {
         //Here call your method
         Resources.load();
      }

      @Override public void render(int width, int height) {}
    }

现在进入您想要使用它的自定义类。

     public class ItemsScreen {
        //----
        private void checkAnswer(int ans) {
            if (ans == 3) {
              //now play music where ever you like in your app. 
              Resources.myMusic1.play();
              Resources.myMusic2.play();
            } else {
              //stop the music from any where in your app.
              Resources.myMusic1.stop();
              Resources.myMusic1.dispose();
              Resources.myMusic3.play();
            }
        }
    }

以上示例适用于所有设备i-e，android，ios，desktop。它经过测试。无论如何，这是一个通用的例子。

libgdx音乐实例从传递的引用中获取，该对象不在Android上播放但在桌面上播放

1 个答案: