$array = array (
'data' =>
array (
'employment' =>
array (
'df1e' =>
array (
0 => '',
),
'dt1e' =>
array (
0 => '',
),
'c1e' =>
array (
0 => '',
),
'p1e' =>
array (
0 => '',
),
'l1e' =>
array (
0 => '',
),
),
'address' =>
array (
'df1a' =>
array (
0 => '',
),
'dt1a' =>
array (
0 => '',
),
'sa1a' =>
array (
0 => '',
),
'c1a' =>
array (
0 => '',
),
'st1a' =>
array (
0 => 'AL',
),
'zc1a' =>
array (
0 => '',
),
),
),
'id' => '709ce406-8fd7-f8ef-6438-53dbbeee4151',
'name' => 'test'
);
上面的数组是根据用户输入生成的。这是地址和工作经历的记录。
df1e
=日期来自。
如果用户输入多个就业历史记录,则可能有多个df1e
字段。如果用户填写了3个表格,则每个数组中的ech值(df1e,dt1e等)将有3个值。
如何迭代此数组并为每个数组插入一条记录?还有地址历史。
每条记录应该是分开的。
这是我的尝试不太有效。它插入一条记录,但值不对。
if($data) {
foreach($data as $history) {
foreach($history['employment'] as $employment) {
$bean->name = $data['name'] . ' - Employment';
$bean->type_c = 'Employment';
$bean->date_from_c = $employment['df1e'];
$bean->date_to_c = $employment['dt1e'];
$bean->company_c = $employment['c1e'];
$bean->position_c = $employment['p1e'];
$bean->location_c = $employment['l1e'];
}
foreach($history['address'] as $address) {
$bean->name = $data['name'] . ' - Address';
$bean->type_c = 'Address';
$bean->date_from_c = $address['df1a'];
$bean->date_to_c = $address['dt1a'];
$bean->street_address_city_c = $address['c1a'];
$bean->street_address_state_c = $address['st1a'];
$bean->street_address_postalcode_c = $address['zc1a'];
$bean->street_address_c = $address['sa1a'];
}
}
$bean->save();
}