Question

我有一个具有这种结构的数组：

Array ( 
[0] => Array ( [key] => Egg Method [values] => Array ( 
    [0] => Array ( [id] => 1 [value] => Boiled ) 
    [1] => Array ( [id] => 2 [value] => Poached ) 
    [2] => Array ( [id] => 3 [value] => Fried ) 
    [3] => Array ( [id] => 4 [value] => Scrambled ) ) ) 

[1] => Array ( [key] => Bread [values] => Array ( 
    [0] => Array ( [id] => 5 [value] => White ) 
    [1] => Array ( [id] => 6 [value] => Brown ) ) ) 

[2] => Array ( [key] => Egg Hardness [values] => Array ( 
    [0] => Array ( [id] => 7 [value] => Soft ) 
    [1] => Array ( [id] => 7 [value] => Medium )    
    [2] => Array ( [id] => 8 [value] => Hard ) ) ) 

)

如何迭代数组以输出所有可能的排列，即

Egg Method: Boiled / Bread: White / Egg Hardness: Soft
Egg Method: Boiled / Bread: White / Egg Hardness: Medium
Egg Method: Boiled / Bread: White / Egg Hardness: Hard
Egg Method: Boiled / Bread: Brown / Egg Hardness: Soft
Egg Method: Boiled / Bread: Brown / Egg Hardness: Medium
Egg Method: Boiled / Bread: Brown / Egg Hardness: Hard
Egg Method: Poached / Bread: White / Egg Hardness: Soft
Egg Method: Poached / Bread: White / Egg Hardness: Medium
Egg Method: Poached / Bread: White / Egg Hardness: Hard
Egg Method: Poached / Bread: Brown / Egg Hardness: Soft
Egg Method: Poached / Bread: Brown / Egg Hardness: Medium
Egg Method: Poached / Bread: Brown / Egg Hardness: Hard
etc etc

另外一个问题是我不知道可能有多少个数组标准，所以不幸的是我不能只使用3个嵌套循环。

我正在使用PHP，虽然我猜伪代码解决方案会很好，我可以适应它。

Answer 1

使用嵌套for循环可以解决您的问题：

for($i=0;$i<Array.length;$i++){
    for($j=0;$j<Array[$i].length;$j++){
        //Echo'ing resultant array element.
        echo $Array[$i][$j];
    }
}

Answer 2

解决了它

recurse("", $partoptions, 0);

function recurse($longstring, $partoptions, $index) {
    $key = $partoptions[$index]['key'];
    $values = $partoptions[$index]['values'];   
    for ($i=0; $i<sizeof($values); $i++) {                  
        $thisvalue = $values[$i]['value'];  
        if (sizeof($partoptions)>$index+1) {
            $tmplongstring = $longstring . ($longstring==""?"":" / ") . $thisvalue;
            recurse($tmplongstring, $partoptions, $index+1);
        } else {
            echo $longstring . " / " . $thisvalue . "<br>";
        }           
    }
}

迭代通过多维数组

2 个答案: