Question

我知道如何使用（简单）key =函数自定义排序。但是如果我需要一个更复杂的key = function，怎么做呢。把它放在一起我有问题。

这是片段：在第一个例子中，我使用key = locale.strxfrm，这对于此目的来说足够好了。第二个例子我使用另一个key = function（itemgetter）。但我需要在一起。

import locale
import operator

locale.setlocale(locale.LC_ALL, "")
# on my computer: German_Germany.1252

lastnames = ["Bange", "Änger", "Amman", "Änger", "Zelch", "Ösbach"]
print(sorted(lastnames, key=locale.strxfrm)) # sorted correct
                                             # alphabetically for Germany
print()

lastnames_firstnames_groups =[
    ["Bange", "Michael", 2],
    ["Änger", "Ämma", 2],
    ["Amman", "Anton", 1],
    ["Änger", "Chris", 2],
    ["Zelch", "Sven", 1],
    ["Ösbach", "Carl", 1]
]
print(sorted(lastnames_firstnames_groups, key=operator.itemgetter(2,0,1)))
# The result is sorted as I expected (the german umlaute are NOT sorted
# the correct way). Is there a way to "add" the string tranformation strxfrm
# as in the first example to this.

任何提示？

Answer 1

听起来你可能想要

print(
    sorted(
        lastnames_firstnames_groups,
        key=lambda t: (t[2], strxfrm(t[0]), strxfrm(t[1]))
    )
)

Answer 2

在已连接，已转换和有序的键上使用strxfrm：

f = operator.itemgetter(2,0,1)
print(sorted(lastnames_firstnames_groups, key=lambda x: locale.strxfrm(' '.join(str(y) for y in f(x)))))

使用键和区域设置对列表进行排序（此处：德语变音符号）

2 个答案: