Question

Stores = ["alpha","bravo","charlie","delta"]
KnownName = Stores.pop()
KnownName2 = Stores.pop()
KnownName3 = Stores.pop()
print KnownName+" "+Stores.pop() 
print KnownName2+" "+KnownName
print KnownName3+" "+KnownName2 
print KnownName3

输出：

delta alpha
charlie delta
bravo charlie
bravo

所以如果我有一个m1，m2，m3 ...... mn的列表我试图随机抽出这样的

m1
m2 m3
m4 m2
m5
m6 m7
m8 m9
m10 m8
m11 m10

如果查看输出，则一行中最多两个值。只有第一个值可以重复。

如何改进我的代码？

foo = ['m1', 'm2', 'm3', 'm4', 'm5','m6','m7','m8']
foo.reverse()
while foo:
    try:
        if random.randrange(0,2) == 0:
            print foo.pop()
        else:
            Value2 = foo.pop()
            print Value2 + " " + foo.pop()
            if random.randrange(0,2) == 0:
                Value3 = foo.pop()
                print Value3 + " " + Value2
            else:
                foo.pop() + foo.pop()
    except:
        break

Answer 1

你可以试试这个。

from random import randint

foo = ['m1', 'm2', 'm3', 'm4', 'm5','m6','m7','m8']
while foo:
    x = randint(0, len(foo) - 1)
    y = randint(0, len(foo) - 1)
    while x == y and len(foo) > 1:
        y = randint(0, len(foo) - 1)
    if randint(0, 1) == 0 or len(foo) <= 1:
        print foo[x]
    else:
        print foo[y], foo[x]
    foo = foo[:x] + foo[x+1:]

列表中的随机输出 - Python

1 个答案: