Question

我的代码是一个信使，通过WiFi将消息从Android设备发送到另一个Android设备。

这是我的代码，在这个课程中我发送消息：

public class ClientThread extends Thread {

    String address;
    String message;
    int portNum;
    InetAddress serverAddr;
    Socket socket;
    PrintWriter out;
    boolean broadcast;

    public ClientThread(String addr, int port, String msg, boolean bcast) throws IOException {
        address = addr;
        portNum = port;
        message = msg;
        broadcast = bcast;
    }

    public void run() {
        try {

            ChatService.portsocket.setBroadcast(broadcast);
            // Charset.forName("UTF-8").encode(message);
            // Log.d("client",new String(message.getBytes()));
            // byte[] b = EncodingUtils.getBytes(message,
            // Charset.forName("UTF-8").name());
            DatagramPacket packet1 = new DatagramPacket(message.getBytes(), message.length(),
                InetAddress.getByName(address), 5555);
            ChatService.portsocket.send(packet1);

        }
        catch (Exception e) {
            e.printStackTrace();
        }
    }
}

在本课程中我收到了以下信息：

public class ChatService extends Service {

    public static String serverIP;
    public static int serverPort = 5555;
    private ServerSocket serverSocket;
    private serverThread sThread;
    public static final String BROADCAST_ACTION = "UpdateEvent";
    public static DatagramSocket portsocket;
    Intent intent;
    int i = 0;

    @Override
    public IBinder onBind(Intent arg0) {
        return null;
    }

    private class serverThread extends Thread {

        public void run() {
            try {
                serverIP = getLocalIpAddress();
                Log.v("addr", serverIP);
                if (serverIP != null) {
                    serverSocket = new ServerSocket(serverPort);
                    Log.v("socket", "created");
                    while (true) {
                        /*
                         * Socket client = serverSocket.accept();
                         * Log.v("client", "received");
                         */
                        try {
                            byte [] buf = new byte [1024];
                            DatagramPacket packet = new DatagramPacket(buf, buf.length);
                            ChatService.portsocket.receive(packet);
                            byte [] result = new byte [packet.getLength()];
                            System.arraycopy(packet.getData(), 0, result, 0, packet.getLength());

                            String msg = new String(result);

                            Log.d("armin", msg);
                            updateGui(msg, packet.getAddress());

                        }
                        catch (Exception e) {
                        }
                    }
                }
            }
            catch (Exception e) {
            }
        }
    }
}

当我输入例如آرمین并发送它时，应用程序收到的消息是一个不连贯的单词，例如آر 有人有想法解决它吗？

Answer 1

如果你有

String message = ...;

将其转换为byte []

byte[] bytes = message.getBytes();

然后必须使用

构造DatagramPacket

new DatagramPacket(bytes, bytes.length(), ... );

您的通话使用

new DatagramPacket( message.getBytes, message.length(),..,

但是这会使用String长度，但是Farsi每个字符需要多个字节。

字符串آرمین有5个字符，但UTF-8编码需要10个字节。你需要发送10个字节。

从具有波斯字符的数据接收字节数组

1 个答案: