是否有任何身体在svgwrite（python）中有一个圆弧切片（奶酪切片或pac-man）的工作示例，我试过这个试图让NorthWest象限在（100,100）处进行，但得到一个奇怪的形状：
w = dwg.path(d="M 100,50 A 50,50 0 0 1 50,100 l 0,50 z", fill="#ffff00", stroke='none')
我查看了inkscape生成的svg的实际输出，这里是xml等价物：
<path
d="M 100,50 A 50,50 0 0 1 50,100 l 0,50 z"
style="fill:#ffff00;fill-opacity:1;fill-rule:nonzero;stroke:none"
sodipodi:type="arc"
sodipodi:cx="100"
sodipodi:cy="100"
sodipodi:rx="50"
sodipodi:ry="50"
sodipodi:start="4.71"
sodipodi:end="3.14"
/>
但是我无法a）获取svgwrite来生成这个b）如果我把svgwrite生成的svg文件替换成它的代码片段，它就没有效果，可能是因为sodipodi命令是特定于inkscape的。
任何人都有这方面的实例吗？
答案 0 :(得分：3)
在阅读更多文档并查看示例
下的链接后，确定http://www.w3.org/TR/SVG11/paths.html#PathData
这是svgwrite
中工作楔的一个例子 w = dwg.path(d="M0,0 v-150 a150,150 0 0,0 -150,150 z",
fill="#00ff00",
stroke="none",
)
这给了我一个西北象限。
我想把我的圈子分成10度切口，所以我写了这段代码：
start_x = 250
start_y = 300
radius = 100
for i in range(36):
degree0 = 0 + i*10
degree1 = 10 + i*10
radians0 = math.radians(degree0)
radians1 = math.radians(degree1)
dx0 = radius*(math.sin(radians0))
dy0 = radius*(math.cos(radians0))
dx1 = radius*(math.sin(radians1))
dy1 = radius*(math.cos(radians1))
m0 = dy0
n0 = -dx0
m1 = -dy0 + dy1
n1 = dx0 - dx1
w = dwg.path(d="M {0},{1} l {2},{3} a {4},{4} 0 0,0 {5},{6} z".format(start_x, start_y, m0, n0, radius, m1, n1),
fill="#00ff00",
stroke="none",
)
elem.append(w)
如果你想运行三角学，那么明确地给了我所有这些切割，也可以明确地使用。这是针对以（250,300）为中心的半径为100的分段。
0 : d=" M 250,300 l 100.0,-0.0 a 100,100 0 0,0 -1.5192246987791975,-17.364817766693033 z "
10 : d=" M 250,300 l 98.4807753012208,-17.364817766693033 a 100,100 0 0,0 -4.511513222629958,-16.837196565873835 z "
20 : d=" M 250,300 l 93.96926207859084,-34.20201433256687 a 100,100 0 0,0 -7.366721700146968,-15.797985667433124 z "
30 : d=" M 250,300 l 86.60254037844388,-49.99999999999999 a 100,100 0 0,0 -9.998096066546069,-14.278760968653934 z "
40 : d=" M 250,300 l 76.60444431189781,-64.27876096865393 a 100,100 0 0,0 -12.325683343243867,-12.325683343243881 z "
50 : d=" M 250,300 l 64.27876096865394,-76.60444431189781 a 100,100 0 0,0 -14.278760968653927,-9.998096066546054 z "
60 : d=" M 250,300 l 50.000000000000014,-86.60254037844386 a 100,100 0 0,0 -15.797985667433132,-7.366721700146968 z "
70 : d=" M 250,300 l 34.20201433256688,-93.96926207859083 a 100,100 0 0,0 -16.837196565873843,-4.511513222629972 z "
80 : d=" M 250,300 l 17.36481776669304,-98.4807753012208 a 100,100 0 0,0 -17.364817766693033,-1.5192246987791975 z "
90 : d=" M 250,300 l 6.123233995736766e-15,-100.0 a 100,100 0 0,0 -17.364817766693037,1.5192246987791975 z "
100 : d=" M 250,300 l -17.36481776669303,-98.4807753012208 a 100,100 0 0,0 -16.83719656587384,4.511513222629958 z "
110 : d=" M 250,300 l -34.20201433256687,-93.96926207859084 a 100,100 0 0,0 -15.79798566743311,7.366721700146968 z "
120 : d=" M 250,300 l -49.99999999999998,-86.60254037844388 a 100,100 0 0,0 -14.278760968653962,9.998096066546069 z "
130 : d=" M 250,300 l -64.27876096865394,-76.60444431189781 a 100,100 0 0,0 -12.325683343243853,12.325683343243867 z "
140 : d=" M 250,300 l -76.6044443118978,-64.27876096865394 a 100,100 0 0,0 -9.998096066546083,14.278760968653948 z "
150 : d=" M 250,300 l -86.60254037844388,-49.99999999999999 a 100,100 0 0,0 -7.366721700146954,15.797985667433103 z "
160 : d=" M 250,300 l -93.96926207859083,-34.20201433256689 a 100,100 0 0,0 -4.511513222629972,16.837196565873864 z "
170 : d=" M 250,300 l -98.4807753012208,-17.364817766693026 a 100,100 0 0,0 -1.5192246987791975,17.364817766693015 z "
180 : d=" M 250,300 l -100.0,-1.2246467991473532e-14 a 100,100 0 0,0 1.5192246987791975,17.364817766693058 z "
190 : d=" M 250,300 l -98.4807753012208,17.364817766693047 a 100,100 0 0,0 4.511513222629958,16.83719656587382 z "
200 : d=" M 250,300 l -93.96926207859084,34.20201433256687 a 100,100 0 0,0 7.366721700146982,15.797985667433146 z "
210 : d=" M 250,300 l -86.60254037844386,50.000000000000014 a 100,100 0 0,0 9.998096066546054,14.278760968653913 z "
220 : d=" M 250,300 l -76.60444431189781,64.27876096865393 a 100,100 0 0,0 12.325683343243867,12.325683343243867 z "
230 : d=" M 250,300 l -64.27876096865394,76.6044443118978 a 100,100 0 0,0 14.278760968653899,9.998096066546054 z "
240 : d=" M 250,300 l -50.00000000000004,86.60254037844385 a 100,100 0 0,0 15.797985667433188,7.3667217001469965 z "
250 : d=" M 250,300 l -34.202014332566854,93.96926207859084 a 100,100 0 0,0 16.83719656587382,4.511513222629958 z "
260 : d=" M 250,300 l -17.364817766693033,98.4807753012208 a 100,100 0 0,0 17.364817766693015,1.5192246987791975 z "
270 : d=" M 250,300 l -1.8369701987210297e-14,100.0 a 100,100 0 0,0 17.364817766693015,-1.5192246987791833 z "
280 : d=" M 250,300 l 17.364817766692997,98.48077530122082 a 100,100 0 0,0 16.8371965658739,-4.511513222629986 z "
290 : d=" M 250,300 l 34.2020143325669,93.96926207859083 a 100,100 0 0,0 15.797985667433117,-7.366721700146968 z "
300 : d=" M 250,300 l 50.000000000000014,86.60254037844386 a 100,100 0 0,0 14.278760968653913,-9.998096066546054 z "
310 : d=" M 250,300 l 64.27876096865393,76.60444431189781 a 100,100 0 0,0 12.325683343243853,-12.325683343243853 z "
320 : d=" M 250,300 l 76.60444431189778,64.27876096865396 a 100,100 0 0,0 9.998096066546054,-14.278760968653913 z "
330 : d=" M 250,300 l 86.60254037844383,50.00000000000004 a 100,100 0 0,0 7.366721700147011,-15.797985667433181 z "
340 : d=" M 250,300 l 93.96926207859084,34.20201433256686 a 100,100 0 0,0 4.511513222629958,-16.83719656587382 z "
350 : d=" M 250,300 l 98.4807753012208,17.36481776669304 a 100,100 0 0,0 1.5192246987791975,-17.364817766693015 z "
答案 1 :(得分：1)
感谢道格拉斯！我把你的弧形绘图答案变成了一个函数，以防它帮助其他人：
def addArc(dwg, current_group, p0, p1, radius):
""" Adds an arc that bulges to the right as it moves from p0 to p1 """
args = {'x0':p0[0],
'y0':p0[1],
'xradius':radius,
'yradius':radius,
'ellipseRotation':0, #has no effect for circles
'x1':(p1[0]-p0[0]),
'y1':(p1[1]-p0[1])}
current_group.add(dwg.path(d="M %(x0)f,%(y0)f a %(xradius)f,%(yradius)f %(ellipseRotation)f 0,0 %(x1)f,%(y1)f"%args,
fill="none",
stroke='red', stroke_width=line_stroke_width
))
# usage example:
import svgwrite
dwg = svgwrite.Drawing(filename="test.svg", debug=True, size=(4000,1000))
current_group = dwg.add(dwg.g(id=name, stroke='red', stroke_width=3, fill='none', fill_opacity=0 ))
addArc(dwg, current_group, p0=[10,10], p1=[40,10], radius=80)
dwg.save()
显然你可以用dwg.line（）跟上上面的弧线绘制函数来绘制饼图片或其他东西。