我想在以下(简化)数据库中应用JPA:
NODE AUTHORITY
----- ----------
idNode int idAuthorities int
nameNode varchar(50) person varchar(255)
idAuthorities int rank int
PRIMARY KEY (idNode) PRIMARY KEY (idAuthorities, rank)
FOREIGN KEY (idAuthorites)
因此,一个节点可以拥有多个权限,并且多个节点可以引用一个权限。
我希望我的课程看起来像:
@Entity
@Table(name="NODE")
public class Node {
private Integer id;
private String nameNode;
private Set<Authority> authorities;
// ... getter and setter normaly annoted for "id" and "nameNode"
@ManyToMany
public Set<Authority> getAuthorities(){
return authorities;
}
// ... setter ...
}
@Entity
@Table(name="AUTHORITY")
public class Authority {
private AuthorityPK pk;
private String person;
privat Set<Node> nodes;
// ... getter and setter normaly annoted for "person"
@Id
public AuthorityPK getPk(){
return this.pk
}
// ... setter ...
@ManyToMany
public Set<Node> getNodes(){
return nodes;
}
// ... setter ...
}
@Embeddable
public class AuthorityPK implements Serializable {
private Integer idAuthorities;
private Integer rankAuthorities;
// override of equals and hashCode
}
但注释&#34; @ ManyToMany&#34;似乎只能用于&#34; @ JoinTable&#34;,在这种情况下,这是不可用的(据我所知)。 有谁知道修改数据库是否有办法?
答案 0 :(得分:2)
JPA不允许这样做,因为它需要外键来引用完整的主键以用于身份识别,并且它可能无法与缓存一起使用。如果可以,我建议使用使用实际主键的关系表切换到更传统的模型。
如果您的提供者允许映射部分pks(我相信Hibernate会这样做),那么你要做的是使用JoinColumn而不是JoinTable制作两个1:M映射,但是将Node-&gt; Authority上的那个映射为insertable = false ,updatable = false
例如:
public class Node {
@Id
private Integer id;
private String nameNode;
@OneToMany
@JoinColumn(name = "idAuthorites", referencedColumnName = "idAuthorites", insertable=false, updatable=false)
private Set<Authority> authorities;
...
public class Authority {
@Id
private AuthorityPK pk;
private String person;
@OneToMany
@JoinColumn(name = "idAuthorites", referencedColumnName = "idAuthorites")
private Set<Node> nodes;
...