Question

我有一个列表，如果我在与列表匹配的文本文件中找到一个单词，那么它必须打印“是”＆＃39;否则打印＆＃39; no＆＃39;。如果我增加列表，那么它会产生一个大的列表。

编码：

keywords=['good','lorry','truck']
with open('qwe.txt','r') as file:
    for line in file:
        for key in keywords:
            if key in line:
               a = 'yes'
            else:
                a = 'no'
            print a

我有一个文本文件qwe.txt：

i havea bike good
condition
yes
I have a car
Skoda Superb
yes good

它的产生：

yes
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
no
yes
no
no

取代Desired：

yes
no
no
no
no
no
yes

请帮助我减少额外的＆＃39; no＆＃39;！

Answer 1

不打印＆＃39;不＆＃39;直到你通过关键字列表完成它：

keywords=['good','lorry','truck']
with open('qwe.txt','r') as file:
    for line in file:
        a = 'no'  # Start by assuming it's not there
        for key in keywords:
            if key in line:
               a = 'yes'
               break  # Now that we've found a match, we can stop looking
        print a

另请注意，您可以使用生成器表达式和any内置函数简化代码：

keywords=['good','lorry','truck']
with open('qwe.txt','r') as file:
    for line in file:
        a = 'yes' if any(key in line for key in keywords) else 'no'
        print a

Answer 2

检查组中的成员资格是set擅长的：

keywords=set(['good','lorry','truck'])
with open('qwe.txt','r') as file:
    for line in file:
        if keywords.intersection(line.split()):
            print 'yes'
        else:
            print 'no'

Answer 3

试试这个

keywords=['good','lorry','truck']
with open('qwe.txt','r') as file:
    for line in file:
        for key in keywords:
            if key in line:
               a = 'yes'
               break
            else:
                a = 'no'
        print a

Answer 4

试试这个：

keywords=['good','lorry','truck']
with open('qwe.txt','r') as file:
    for line in file:
        found_match="no"
        for key in keywords:
            if key in line:
                found_match="yes"
        print found_match

要小心你的缩进。对于每个＆＃34;行＆＃34;，每个＆＃34;键＆＃34;都有一个print语句。使用3个键和6个键（如果底部有一个空行，可能是7个），你会得到3 * 6 = 18个响应。

python for循环使额外的列表

4 个答案: