python帮助列出嵌套for循环中的值

Question

如何访问第二个列表（val）中的值？

colors = [('teal','30a8a0'),('pink','b33b96'),('red','de3249'),('green','758f3d'),('purple','532c86'),('darkblue','116da4'),('skyblue','1d9dc5')]
darkblue=[('first'),('second')]

for (color,value) in colors:
    print color #teal, pink, red, etc...
    for (val) in {color}:
        print val #first, second, etc...

Answer 1

这个怎么样？

subcolors = {'darkblue': ['first', 'second'],
             'teal': ['first-teal', 'second-teal'],
             'pink': ['first-pink', 'second-pink'],
             # etc..
            }

for (color,value) in colors:
    print color #teal, pink, red, etc...
    for val in subcolors[color]:
        print val #first-teal, second-teal, first-pink, second-pink, etc...

通过将颜色放入dict中，我们可以更轻松地检索它们并迭代它们的值。

---

如果你真的想从darkblue变量中做到并且你不想使用dict，你可以这样做，但我不推荐它：

darkblue = ['first', 'second']
teal = ['first-teal', 'second-teal']
pink = ['first-pink', 'second-pink']
# etc...

for (color,value) in colors:
    print color #teal, pink, red, etc...
    for val in locals()[color]:
        print val #first-teal, second-teal, first-pink, second-pink, etc...