Question

在牌组上拖了52张牌之后摆脱所有Aces的算法是什么？输出结果中不允许使用Aces。

<?php
function pc_array_shuffle($array) {
    $i = count($array);

    while(--$i) {
        $j = mt_rand(0, $i);

        if ($i != $j) {
            // swap elements
            $tmp = $array[$j];
            $array[$j] = $array[$i]; 
            $array[$i] = $tmp;
        }
    }

    return $array;
}

$suits = array('Clubs', 'Diamonds', 'Hearts', 'Spades');
$cards = array('Ace', 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King');

$deck = pc_array_shuffle(range(1, 52));


$n=1;
while(($draw = array_pop($deck)) != NULL) {

    echo $n.') '.$cards[$draw / 4] . ' of ' . $suits[$draw % 4] . '<br />';
    $n++;
}
?>

http://codepad.org/yUrrT2m1

Answer 1

尝试一下：

$suits = array('Clubs', 'Diamonds', 'Hearts', 'Spades');
$cards = array('Ace', 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King');
$deck = array();
$no_aces = array();

// build array of cards
foreach ($cards as $card){
    foreach ($suits as $suit){
        $deck[] = $card . " of " . $suit;
    }
}

// shuffle deck - see what I did there? ;)
shuffle($deck);

// add shuffled cards to another array while removing the aces
foreach($deck as $card){
    $pos = strrpos(strtolower($card), "ace");
    if ($pos === false) {
        // not an ace, add to array
        $no_aces[] = $card;
    }
}

// $no_aces array now contains all the shuffled cards without the aces
var_dump($no_aces);

Answer 2

我只是在那里抛出疯狂的猜测，但是......

$n=1;

while(($draw = array_pop($deck)) != NULL) {
    $card = $cards[$draw / 4];

    if (strtolower($card) != 'ace') {
        echo $n.') '.$card . ' of ' . $suits[$draw % 4] . PHP_EOL;
    }

    $n++;
}

http://codepad.org/JyDeOR7d

PHP在洗牌后摆脱所有Aces

2 个答案: