我有一个时间列$data['Time'] (hh:mm:ss)
,我需要将其转换为分钟。我怎样才能做到这一点?当我写这样的时候:
$avg = ($data['Kilometers'] / $data['Time']) * 60;
我有这个错误
Warning: Division by zero in ... on line ..
答案 0 :(得分:8)
$time = explode(':', $data['Time']);
$minutes = ($time[0] * 60.0 + $time[1] * 1.0);
$avg = $minutes > 0 ? $data['Kilometers'] / $minutes : 'inf'; // if time stored is 0, then average is infinite.
将时间戳转换为分钟的另一种方法是,
$time = date('i', strtotime($data['Time']);
答案 1 :(得分:5)
尝试这样的事情:
function minutes($time){
$time = explode(':', $time);
return ($time[0]*60) + ($time[1]) + ($time[2]/60);
}
答案 2 :(得分:1)
You can use following function
<?php
function date2min ($hms) {
$fromTime = strtotime($hms);
$getMins = round(abs($fromTime) / 60,2);
return $getMins;
}
$date = date('H:i:s'); // $data['Time'] your desired time
$myResult = date2min($date);
and then use $myResult value according to your need.
?>
答案 3 :(得分:1)
如果hh:mm:ss是一个刺痛你可以试试这个经过测试并且有效:
$hour=substr($string, 0,1);// we get the firs two values from the hh:mm:ss string
$hour=(int)$hour;
$hourtomin=$hour*60;// after we have the hour we multiply by 60 to get the min
$min=substr($string, 3,4);//now we substring 3 to 4 because we want to get only
// the min and we dont want to get the : which is in position 2
$min=(int)$min;
$totalmin=$hourtomin+$min;// we just do a simple calc to calculate all the min
echo $totalmin;
答案 4 :(得分:1)
这是一个简单的计算使用这个
$time='01:02:10';
$timesplit=explode(':',$time);
$min=($timesplit[0]*60)+($timesplit[1])+($timesplit[2]>30?1:0);
echo $min.' Min' // 62 Min
答案 5 :(得分:0)
function hourMinute2Minutes($strHourMinute) {
$from = date('Y-m-d 00:00:00');
$to = date('Y-m-d '.$strHourMinute.':00');
$diff = strtotime($to) - strtotime($from);
$minutes = $diff / 60;
return (int) $minutes;
}
echo hourMinute2Minutes('01:30'); // 90
答案 6 :(得分:0)
您可以使用这种非常简单的方法。
$minutes=$item['time_diff'];
$hours = sprintf('%02d',intdiv($minutes, 60)) .':'. ( sprintf('%02d',$minutes % 60));
return $hours;
输出将 09:10