将HH：MM：SS字符串转换为分钟数

Question

我有以下查询。

select cast(dateadd(minute, datediff(minute, TimeIn, TimeOut), 0) as time(0) )

我从hrs-min-seconds格式的两列中获得结果。 我想以min的格式。因此02:47:00会读取167。

Answer 1

对于SQL Server（也适用于2005年）：

select Datediff(mi,convert(datetime,'00:00:00',108), convert(datetime,'02:47:00',108))

Answer 2

SQL Server查询：

SELECT cast(substring('02:47:00',1,2) AS int)*60+
       cast(substring('02:47:00',4,2) AS int)+ 
       cast(substring('02:47:00',7,2) AS int)/60.0 AS minutes

MYSQL查询：

SELECT TIME_TO_SEC('02:47:00') / 60

结果：

| MINUTES |
-----------
|     167 |

Answer 3

宣布@Time DATETIME = '01：05：00'

选择（（DATEPART（HOUR，@ Time）* 60）+（DATEPART（MINUTE，@ Time）））

Answer 4

试试这个：

datediff(minute, 0, '02:47')

Answer 5

扩大贾斯汀的答案。这允许小时数大于2位的情况。

${HOME}/libs/rxjava-1.3.1-SNAPSHOT

结果：

declare @time varchar(50) = '102:47:05'

SELECT cast(right(@time,2) AS int)+
       cast(left(right(@time,5),2) AS int)*60+ 
       cast(left(@time,len(@time)-6) AS int)*3600 AS seconds,
       (cast(right(@time,2) AS int)+
       cast(left(right(@time,5),2) AS int)*60+ 
       cast(left(@time,len(@time)-6) AS int)*3600)/60.0 AS minutes

Answer 6

SELECT DATEDIFF(minute,CAST('00:00' AS TIME), CAST('02:47' AS TIME)) AS difference

给你：

| DIFFERENCE |
--------------
|        167 |

Answer 7

$time = '02:47:00';

$time = explode(":",$time); 

$total = ($a[0]*60)+$a[1];

echo 'Minutes : '.$total;<br>
echo 'Seconds : '.$a[2];

Answer 8

不幸的是，如果您要对超过24小时的值使用DATEPART函数，则会收到错误消息：

  

从字符串转换日期和/或时间时转换失败。”

您可以使用以下代码对其进行测试：

declare @Time DATETIME = '32:00:00'
select ((DATEPART(HOUR, @Time)*60) + (DATEPART(MINUTE, @Time)))

为解决此问题，我使用了另一种方法：

declare @tbl table(WorkHrs VARCHAR(8))
insert into @tbl(WorkHrs) values ('02:47:00')
insert into @tbl(WorkHrs) values ('32:00:00')
-- Sum in minutes
SELECT TRY_CAST(([HOURS] * 60) + [MINUTES] + ([SECOND] / 60) AS INT) as TotalInMinutes
FROM (
SELECT 
    -- Use this aproach to get separated values 
    SUBSTRING(WorkHrs,1,CHARINDEX(':',WorkHrs)-1) AS [HOURS],
    SUBSTRING(WorkHrs,4,CHARINDEX(':',WorkHrs)-1) AS [MINUTES],
    SUBSTRING(WorkHrs,7,CHARINDEX(':',WorkHrs)-1) AS [SECOND] -- probably you can ignore this one
    FROM @tbl
)
tbl
-- Sum in seconds
    SELECT TRY_CAST(([HOURS] * 3600) + ([MINUTES] * 60) + [SECOND] AS INT) as TotalInSeconds
    FROM (
    SELECT 
    -- Use this aproach to get separated values 
    SUBSTRING(WorkHrs,1,CHARINDEX(':',WorkHrs)-1) AS [HOURS],
    SUBSTRING(WorkHrs,4,CHARINDEX(':',WorkHrs)-1) AS [MINUTES],
    SUBSTRING(WorkHrs,7,CHARINDEX(':',WorkHrs)-1) AS [SECOND]
    FROM @tbl
)
tbl

此代码将返回如下：