Question

我正在制作一个摇滚纸剪刀游戏。这就是我到目前为止所拥有的。我在使用函数determineOutcome时遇到问题。我试图让结果将计算机的结果恢复为摇滚，纸张或剪刀。不是randomNumber（），1,2或3.我真的很感谢你的帮助。这是我的代码：

btnPlay.addEventListener(MouseEvent.CLICK, playGame);
btnNewGame.addEventListener(MouseEvent.CLICK, newGame);

var ties:int = 0;
var wins:int = 0;
var losses:int = 0;

function playGame(e:MouseEvent):void
{
    var userThrow:int;
    var computerThrow:int;
    var outcome:String;

    userThrow = int(radRock.group.selectedData);
    computerThrow = randomWholeNumber(3,1);
    outcome = determineOutcome(userThrow, computerThrow);

    lblOutcome.text = outcome;  
    lblScore.text = "Wins: " + wins.toString() + "  Losses: " + losses.toString() + "Ties: " + ties.toString();
}


function newGame(e:MouseEvent):void
{
    //
}


function randomWholeNumber(highNumber:int,lowNumber:int):int
{
    return Math.floor((highNumber - lowNumber + 1) * Math.random() + lowNumber);
}


function determineOutcome(u:int,c:int):String
{
    if(u == 2 && c == 1){
        return "The computer threw a rock and your paper covered it. You Win!"
    }

    else if(u == 3 && c == 2){
        return "The computer threw paper and your scissors cut the paper.You Win!"
    }

    else if(u == 1 && c == 3){
        return "The computer threw scissors and your rock smashed it. You Win!"
    }

    else if(u == c){
        return "You tied with the computer"
    }

    else if(u == 1 && c == 2){
        return "you threw a rock and the Computer's paper covered it. You lose :("
    }

    else if(u == 2 && c == 3){
        return "You threw paper and the Computer's scissors cut your paper.You lose :("
    }

    else if(u == 3 && c == 1){
        return "You threw scissors and the Computer's rock smashed it. You lose :("
    }
}

Answer 1

此函数会抛出编译器错误，因为默认情况下它不会返回值。我的意思是在条件之外没有退货声明。如果不符合其中一个条件，您总是需要在外面使用退货声明。在最后，只需添加return＆＃34;＆＃34 ;;或返回null;

ROCK-PAPER-SCISSORS ActionScript 3.0

1 个答案: