背景

Question

背景

我们说我有Address个对象：

public class Address_Model{
     public int Id {get; set;}
     public string Street{get; set;}
     public string City {get; set;}
     public string State {get; set;}
     public string PostalCode{get; set;}
}

此属性用于其他几个对象（即office对象，home对象等）：

public class Office_Model{
     public int Id {get; set;}
     public Address_Model Address{get; set;}
     //. . . (other properties specific to the office model)
}

public class Home_Model{
     public int Id {get; set;}
     public Address_Model Address{get; set;}
     //. . . (other properties specific to the home model)
}

这些模型存在于我的BLL中。在我的构造函数中，它使用来自我的DAL的数据，我当前手动构造Address属性：

public Office_Model GetOffice(int id){

var office = DAL.SomeClass.GettOfficeById(id);

return new Office_Model
{
   Id = office.Id,
   Address = new Address_Model{
       Id = office.Address.Id,
       Street = office.Address.Street,
       City = office.Address.City,
       State = office.Address.State,
       PostalCode = office.Address.PostalCode
   }
}

}

public Home_Model GetHome(int id){

var home = DAL.SomeClass.GettHomeById(id);

return new Home_Model
{
   Id = home.Id,
   Address = new Address_Model{
       Id = home.Address.Id,
       Street = home.Address.Street,
       City = home.Address.City,
       State = home.Address.State,
       PostalCode = home.Address.PostalCode
   }
}

}

为了增加代码的可维护性（例如，不必将Street2这样的新属性添加到构造Address_Model的所有位置），我想创建一个构造地址的通用方法模型：

public Address_Model GetAddressModel(DAL.SomeClass.Address address){

     return new Address_Model{
           Id = address.Address.Id,
           Street = address.Address.Street,
           City = address.Address.City,
           State = address.Address.State,
           PostalCode = address.Address.PostalCode
     }

}

现在我的BLL getter方法看起来更像是这样：

  public Office_Model GetOffice(int id){

    var office = DAL.SomeClass.GettOfficeById(id);

    return new Office_Model
    {
       Id = office.Id,
       Address = GetAddressModel(office.Address);
    }

    }

    public Home_Model GetHome(int id){

    var home = DAL.SomeClass.GettHomeById(id);

    return new Home_Model
    {
       Id = home.Id,
       Address = GetAddressModel(home.Address);
    }

    }

问题

委派此施工作业是否会产生负面影响？我是性能分析的新手，刚刚了解了boxing和unboxing;我不确定这种性能下降是否适用于我在这里所做的事情。

显然，我在很大程度上简化了这个例子。实际上，还有许多需要构建的嵌套对象。

Answer 1

来自MSDN的

Boxing：

拳击是将值类型转换为类型对象或的过程到此值类型实现的任何接口类型。

由于您的Address对象是引用类型（标记为class而不是struct），并且您希望收到Address类型作为参数，你的代码中不会发生拳击。更重要的是，JIT编译器可能决定内联您的方法调用，这将消除为该调用一起创建新的堆栈帧。

在创建公共对象构造函数时是否存在性能影响？

背景

问题

1 个答案: