Question

嗨，我对编程和编程课程的介绍完全陌生，我对这个作业有一些问题。我需要一些帮助来解决问题，即创建一个输出总降雨量，平均降雨量，最大降雨量和最小降雨量的程序。一切都很好，直到输出的最小降雨量保持输出为0.0。

#include <stdio.h>
#include <stdlib.h>
#define SIZE 5

double getValidRainfall(){
    double result;

    printf("Enter a rainfall amount: ");
    scanf("%lf", &result);

    while (result < 0.0){
        printf("%.2lf is not a valid rainfall amount.", result);
        printf("\nEnter a rainfall amount: ");
        scanf("%lf", &result);
    }

    return result;
}

double calculateTotal (double rainfall[], int size){
    double result = 0.0;
    int i;
    for(i = 0; i < size; i++){
        result += rainfall[i];
    }
    return result;
}

double findLargest(double rainfall[], int size){
    double result = 0.0;
    int i;
    for (i = 0; i < size; i++) {
        if(rainfall[i] > result)
            result = rainfall[i];
    }
    return result;
}

// I believe the problem is located right under here and...

double findSmallest(double rainfall[], int size){
    double result = 0.0;
    int i;
    for (i = 0; i < size; i++) {
        if(rainfall[i] < result)
            result = rainfall[i];
    }
    return result;
}

    // here.. Just can't seem to find the issue that will output the correct smallest
    // amount of rainfall.

int main(){
    double rainfall[SIZE], totalRainfall, averageRainfall;
    double largestRainfall, smallestRainfall;
    int i;

    for( i = 0; i < SIZE; i++)
        rainfall[i] = getValidRainfall();


    totalRainfall = calculateTotal(rainfall, SIZE);
    averageRainfall = totalRainfall / SIZE;
    largestRainfall = findLargest(rainfall, SIZE);
    smallestRainfall = findSmallest(rainfall, SIZE);

    printf("Thank you\n");
    printf("The total rainfall is %.2lf\n", totalRainfall);
    printf("The average rainfall is %.2lf\n", averageRainfall);
    printf("The largest daily rainfall is %.1lf\n", largestRainfall);
    printf("The smallest daily rainfall is %.1lf\n", smallestRainfall);
}

Answer 1

在findSmallest中，您可以开始：

double result = 0.0;

然后，只有在降雨量较小时才更新。但是，假设没有地方有负降雨，这意味着它仍然会以0.0结尾。

要使此算法有效，您应该以至少与实际降雨量一样高的值启动它，例如

 if ( size == 0 )
     return 0.0;

 double result = rainfall[0];

Answer 2

在findSmallest中，将result初始化为一个大数字，大于所有可能性。

E.g，

#include <float.h>

double result = DBL_MAX;

Answer 3

问题是你在findSmallest函数中将结果初始化为0.0。除非您有负降雨，否则您将永远找不到比这更小的东西。相反，将结果初始化为该函数中的较大值。

Answer 4

尝试以下：

double findSmallest(double rainfall[], int size){
double result = 0.0;
int i;
for (i = 0; i < size; i++) {
if(i == 0)
    result = rainfall[i];
if(rainfall[i] < result)
    result = rainfall[i];
}
return result;

代码在问题出现时是不言自明的。

Answer 5

这是因为findSmallest以0.0的假设开始，然后寻找负降雨。请使用rainfall[]中的第一个值作为初始值。

坚持在C的任务

5 个答案: