我被困在家庭作业委员会计算上

时间:2013-06-27 19:08:38

标签: java

我需要比较至少三个人的年度总销售额。我需要我的应用程序来计算每个必须达到的额外金额才能达到或超过最高收入者。我想出了大部分内容并且知道如果在场景中只有两个人,如何做到这一点,但获得第三个等式是让我循环!任何帮助表示赞赏,并提前致谢!这是我到目前为止所做的,但显然最终计算结果不正确。

package Commission3;
import java.util.Scanner;
public class MainClass {

    public static void main(String[] args) {
        // Create a new object AnnualCompensation
        Commission3 salesPerson[] = new Commission3[2];
        // creat two object
        salesPerson[0] = new Commission3();
        salesPerson[1] = new Commission3();
        salesPerson[2] = new Commission3();
        //new scanner input
        Scanner keyboard = new Scanner(System.in);

        //get salesperson1 name
        System.out.println("What is your first salesperson's name?");
        salesPerson[0].name = keyboard.nextLine();

        //get salesperson1 sales total
        System.out.println("Enter annual sales of first salesperson: ");
        double val = keyboard.nextDouble();
        salesPerson[0].setAnnualSales(val);

        //get salesperson2 name
        System.out.println("What is your second salesperson's name?");
        salesPerson[1].name = keyboard.next();


        //get salesperson2 sales total
        System.out.println("Enter annual sales of second salesperson: ");
        val = keyboard.nextDouble();
        salesPerson[1].setAnnualSales(val);

        //get salesperson3 name
        System.out.println("What is your third salesperson's name?");
        salesPerson[2].name = keyboard.next();


        //get salesperson3 sales total
        System.out.println("Enter annual sales of third salesperson: ");
        val = keyboard.nextDouble();
        salesPerson[2].setAnnualSales(val);


        double total1, total2, total3;
        total1 = salesPerson[0].getTotalSales();
        System.out.println("Total sales of " + salesPerson[0].name +" is: $" + total1);
        total2 = salesPerson[1].getTotalSales();
        System.out.println("Total sales of " + salesPerson[1].name +" is: $" + total2);
        total3 = salesPerson[2].getTotalSales();
        System.out.println("Total sales of " + salesPerson[2].name +" is: $" + total3);
        if (total1 > total2) {
            System.out.print("Salesperson " + salesPerson[2].name + "'s additional amount 
        of sales that he must " + " achieve to match or exceed the higher of the 
        salesperson " + salesPerson[0].name);  
            System.out.println(" $" + (total1 - total2));
        } else if (total2 > total1) {
            System.out.print("Salesperson " + salesPerson[0].name + "'s additional amount
        of sales that he must " + " achieve to match or exceed the higher of the 
        salesperson " +  salesPerson[1].name);

            System.out.println(" $" + (total2 - total1));
        } else {
            System.out.println("Both have same compensation $" + total1);
        }
    }
}

1 个答案:

答案 0 :(得分:5)

当您从用户那里获取输入时,记录到目前为止的最高销售额,以及销售额最高的销售人员的姓名。

然后,您可以遍历所有三个,而不是检查total1和total2,并将它们与最大值进行比较。如果当前总数小于最大值,则计算差值。否则,当前总数等于最大值,您无需进行计算。

我会留下实际代码让你弄明白。