Question

我正在尝试将我的UITableView中显示的图像传递给我的细节UITableView。我的tableview中的图像是从JSON端点提取的。知道我怎么能这样做吗？目前，这是我的应用程序崩溃的一行：

featureImage.image = [[articleDetail objectForKey：@“Image”] objectForKey：@“filename”];

知道我怎么能这样做吗？请参阅下面的代码。

TableViewController.m

   - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{

    FullArticleViewController *detailViewController = [[FullArticleViewController alloc]
                                                        initWithNibName:@"FullArticleViewController" bundle:nil];
    detailViewController.title = [[Doctors objectAtIndex:indexPath.row] objectForKey:@"node_title"];
    detailViewController.articleDetail = [Doctors objectAtIndex:indexPath.row];

    [detailViewController.featureImage sd_setImageWithURL:[NSURL URLWithString:cellImageLink]];

    [self.navigationController pushViewController:detailViewController animated:YES];

}

DetailViewController.h

{

    IBOutlet UIScrollView *scroller;
    IBOutlet UILabel *firstnameLabel;
    IBOutlet UILabel *descriptionLabel;
    IBOutlet UILabel *bodyLabel;
    IBOutlet UIImageView *featureImage;

}

@property (nonatomic, copy) NSDictionary *articleDetail;
@property (strong, nonatomic) UIImageView *featureImage;
@property (strong, nonatomic) NSString *cellImageLink;

DetailViewController.m

- (void)viewDidLoad
{

    [scroller setScrollEnabled:YES];
    [scroller setContentSize:CGSizeMake(320, 5000)];

    [super viewDidLoad];
    // Do any additional setup after loading the view from its nib.



firstnameLabel.text = [articleDetail objectForKey:@"node_title"];
descriptionLabel.text = [articleDetail objectForKey:@"Opening Paragraph"];
bodyLabel.text = [articleDetail objectForKey:@"Body"];
featureImage.image = [articleDetail sd_setImageWithURL:[NSURL URLWithString:cellImageLink]];

}

Answer 1

如果你使用像SDWebImage这样的东西，那么你可以调用上面的相同代码：

[detailViewController.featureImage setImageWithURL:[NSURL URLWithString:secondLink]];

如果图像已下载，它会从缓存中提取图像，否则会将其下载。

如何将UITableView中的图像传递给我的细节UITableView？

1 个答案: