Question

这是我当前的XML文件，它为我提供了不同角色的对话，或者至少它应该。我想让它工作，以便我可以指定实体ID和选项/任务ID并获取输出。所以我该怎么做？感谢任何帮助，非常感谢。

<?xml version="1.0"?>
<dialoge>
<entity id="1"> <!-- questgiver -->
    <quest id="1">
        <option id="1">
            <precondition>player has not started quest</precondition>
            <output>hello there, can you kill 2 enemies for me?</output>
        </option>
        <option id="2">
            <precondition>player has completed quest and player has not...</precondition>
            <output>thankyou, have a sword for your troubles.</output>
        </option>
        <option id="3">
            <precondition>player has not finished quest</precondition>
            <output>you haven't finished yet.</output>
        </option>
        <option id="4">
            <outpur>thank you.</outpur>
        </option>
    </quest>
</entity>
<entity id="2"> <!-- villager -->
    <option id="1">
        <precondition>village is being destroyed</precondition>
        <output>our village is being destroyed, please help us!</output>
    </option>
    <option id="2">
        <precondition>village has been saved or destroyed</precondition>
        <output>we will never forget this.</output>
    </option>
    <option id="3">
        <output>hello.</output>
    </option>
</entity>
</dialoge>

这是我目前拥有的，但它不起作用。我知道这可能是一个愚蠢的问题，但我无法在网络上的任何地方找到答案。感谢。

public static void read() {
    try {
        File file = new File("text.xml");
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document doc = db.parse(file);
        doc.getDocumentElement().normalize();

        System.out.println("root of xml file " + doc.getDocumentElement().getNodeName());
        NodeList nodes = doc.getElementsByTagName("entity");
        System.out.println("==========================");

        for(int i = 0; i < nodes.getLength(); i++) {
            Node node = nodes.item(i);
            if(node.getNodeType() == Node.ELEMENT_NODE) {
                Element element = (Element) node;
                        if(element.getElementsByTagName("entity").item(0).getTextContent().equals("output")) {

                }
                System.out.println("" + getValue("output", element));
            }
        }
    }catch(Exception e) {
        e.printStackTrace();
    }
}

private static String getValue(String tag, Element element) {
    NodeList nodes = element.getElementsByTagName(tag).item(0).getChildNodes();
    Node node = (Node) nodes.item(0);
    return node.getNodeValue();
}

Answer 1

最简单的方法可能是使用XPath ...

try {
    File file = new File("text.xml");
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document doc = db.parse(file);
    doc.getDocumentElement().normalize();

    XPath xpath = XPathFactory.newInstance().newXPath();
    XPathExpression xExpress = xpath.compile("//*[@id='1']");
    NodeList nl = (NodeList) xExpress.evaluate(doc, XPathConstants.NODESET);
    System.out.println("Found " + nl.getLength() + " matches");
} catch (Exception e) {
    e.printStackTrace();
}

xpath查询//*[@id='1']将查找文档中属性id的所有节点，其值为1

有关XPath

的详细信息，请查看WC3 XPath Tutorial和How XPath works

Answer 2

通常，DOM更容易使用，但是在开始使用它之前解析entire XML的开销在SAX parser正在解析XML并且遇到标记开始时（例如{{} 1}}），然后它触发<something>事件（事件的实际名称可能不同）。 read more..

请参阅Parsing an XML File Using SAX

上的 Java Tutorial

以下是示例代码：

startElement

如何通过元素id读取XML？

2 个答案: