Question

这样的功能：

getElementDom("root.child.grandchild")

返回grandchild元素。

Answer 1

是的，它被称为XPath：

from cStringIO import StringIO
import xml.etree.ElementTree 
from xml.etree import ElementTree as ET

doc = StringIO("""
<document>
 <title>People working for me</title>
 <person xmlns:foaf="http://xmlns.com/foaf/0.1/"
         xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#">
   <name>Jim</name>
   <title>Porch Light Switcher</title>
   <foaf:homepage rdf:resource="http://example.com/his_page" />
 </person><person>
   <name>Joe</name>
   <title>Bottle Washer, 3rd class</title>
   <nick xmlns="http://xmlns.com/foaf/0.1/">Joe-Joe</nick>
 </person>
</document>
""")

tree = ET.parse(doc)
print tree.findall("person/title")

当然，lxml要好得多：

f = StringIO('<foo><bar></bar></foo>')
tree = etree.parse(f)
r = tree.xpath('/foo/bar')

Answer 2

DOM标准中没有这样的功能，没有。您可能希望使用lxml library代替并使用XPath表达式：

from lxml import etree

tree = etree.parse(filename)
for element in tree.xpath('./root/child/grandchild'):

lxml建立在ElementTree API之上而不是（古老的）DOM API之上。标准库ElementTree API实现也支持有限的XPath表达式搜索：

from xml.etree import ElementTree

tree = ElementTree.parse(filename):
for element in tree.find('./root/child/grandchild'):

是否有通过其DOM地址获取元素的函数？

2 个答案: