我想从有多个电话号码的联系人中选择一个电话号码。 这可以通过Android自己的联系人列表完成吗? 我设法将所有联系人列出:
Intent intent = new Intent(Intent.ACTION_PICK, Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);
我选择,让我们说," John Doe"我知道,有3个电话号码。 反正有没有让Android本身向我展示那些使用意图的3个电话号码?
答案 0 :(得分:0)
首先,让我们调用选择器
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);
然后在onActivityResult()中让我们检查所选联系人的号码数量,如果数字> 1,则让我们显示一个对话框来选择一个:
Uri result = data.getData();
Log.v(TAG, "Got a result: " + result.toString());
// get the contact id from the Uri
String id = result.getLastPathSegment();
// query for phone numbers for the selected contact id
c = getContentResolver().query(
Phone.CONTENT_URI, null,
Phone.CONTACT_ID + "=?",
new String[]{id}, null);
int phoneIdx = c.getColumnIndex(Phone.NUMBER);
int phoneType = c.getColumnIndex(Phone.TYPE);
if(c.getCount() > 1) { // contact has multiple phone numbers
final CharSequence[] numbers = new CharSequence[c.getCount()];
int i=0;
if(c.moveToFirst()) {
while(!c.isAfterLast()) { // for each phone number, add it to the numbers array
String type = (String) Phone.getTypeLabel(this.getResources(), c.getInt(phoneType), ""); // insert a type string in front of the number
String number = type + ": " + c.getString(phoneIdx);
numbers[i++] = number;
c.moveToNext();
}
// build and show a simple dialog that allows the user to select a number
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle(R.string.select_contact_phone_number_and_type);
builder.setItems(numbers, new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int item) {
String number = (String) numbers[item];
int index = number.indexOf(":");
number = number.substring(index + 2);
loadContactInfo(number); // do something with the selected number
}
});
AlertDialog alert = builder.create();
alert.setOwnerActivity(this);
alert.show();
} else Log.w(TAG, "No results");
} else if(c.getCount() == 1) {
// contact has a single phone number, so there's no need to display a second dialog
}